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3 years ago

The ordered pairs on the graph represent a proportional relationship. What is the constant of proportionality of y to x

Mathematics

2 answers:

Serjik [45]3 years ago

8 0

Answer:

the answer is C

Step-by-step explanation:

a proportional relationship" refers to the presence of a constant of variation between variables, that is, variables must variate at the same rate, where such rate is call the constant of proportionality. Notice that the second table fulfils this definion, because x-variable variates 2 units, while y-variable variates ten units.

Ainat [17]3 years ago

6 0

Answer:

i think it’s C

Step-by-step explanation:

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Novay_Z [31]

Answer:

the answer is 10!!!

Step-by-step explanation:

sorry if me woring

3 0

3 years ago

The Magazine Mass Marketing Company has received 16 entries in its latest sweepstakes. They know that the probability of receivi

Elena-2011 [213]

Answer:

P(X>4)= 0.624

Step-by-step explanation:

n = 10

p= 0.5 ,q= 1 - p = 0.5

Two fifth of 10 = 2/5 x 10 =4

It means that we have to find probability P(X>4).

P(X>4)= 1 -P(X=0)-P(X=1)-P(X=2)-P(X=3)-P(X=4)

We know that

P(X>4)= 1 -P(X=0)-P(X=1)-P(X=2)-P(X=3)-P(X=4)

P(X>4)= 1 -0.0009 - 0.0097 - 0.043 - 0.117-0.205

8 0

3 years ago

Write the quadratic equation that has roots (√3+1)/2 and (√3 -1 )/2, if its coefficient with x^2 is equal to:

NISA [10]

Answer:

The equation is: $x^2-x+\frac{1}{2}$

(A) $x^2-x+\frac{1}{2}=0$

(B) $5x^2-5x+\frac{5}{2}=0$

$-\frac{1}{2}x^2+\frac{1}{2}x-\frac{1}{4}=0$

d) √3

$(\sqrt{3}) x^2-x\sqrt{3}+\frac{\sqrt{3}}{2}=0$

Step-by-step explanation:

If the roots of the quadratic equation are: $\frac{\sqrt{3}+1}{2} and \frac{\sqrt{3}-1}{2}$

This means:

x= $\frac{\sqrt{3}+1}{2}$ OR $x= \frac{\sqrt{3}-1}{2}$

x- $x-\frac{\sqrt{3}+1}{2}=0 \: or\: x- \frac{\sqrt{3}-1}{2}=0$ =0 or x-

If a=0 or b=0, then ab=0

Therefore:

$(x-\frac{\sqrt{3}+1}{2})(x-\frac{\sqrt{3}-1}{2})=0\\x^2-\frac{x(\sqrt{3}-1)}{2}-\frac{x(\sqrt{3}+1)}{2}+(\frac{\sqrt{3}-1)}{2})(\frac{\sqrt{3}+1}{2})=0\\x^2-x+\frac{1}{2}=0$

Therefore the coefficient of $x^2$ here is 1.

b) To make 5 the coefficient of $x^2$

Simply multiply $x^2-x+\frac{1}{2}=0$ by 5

This gives: $5x^2-5x+\frac{5}{2}=0$

c) $-\frac{1}{2}$

To make $-\frac{1}{2}$ the coefficient of $x^2$

Simply multiply $x^2-x+\frac{1}{2}=0$ by $-\frac{1}{2}$

This gives: $-\frac{1}{2}x^2+\frac{1}{2}x-\frac{1}{4}=0$

d) √3

To make $\sqrt{3}$ the coefficient of $x^2$

Simply multiply $x^2-x+\frac{1}{2}=0$ by $\sqrt{3}$

This gives: $(\sqrt{3}) x^2-x\sqrt{3}+\frac{\sqrt{3}}{2}=0$

5 0

3 years ago

How do u do this (y–4)(4y+2)

Bess [88]

This is binomial distributing, or at least that's what my teacher called it.

(y-4)(4y+2)

Use the FOIL method (First, Outside, Inside, Last)

Start with y(4y)

The rest is all up to you!

6 0

2 years ago

Read 2 more answers

Which best describes the complement of spinning any number less than 3?

Alisiya [41]

Answer:

spinning a 1 or 2

Step-by-step explanation:

less than 3 is 1 or 2

3 0

2 years ago