Answer:
Which of the following is NOT true about a rhombus?
options:
lines of symmetry are the perpendicular bisectors
lines of symmetry are the diagonals
a rhombus has four congruent sides
a rhombus is a quadrilateral
Answer:
Third option
Step-by-step explanation:
We can't factor this so we need to use the quadratic formula which states that when ax² + bx + c = 0, x = (-b ± √(b² - 4ac)) / 2a. However, we notice that b (which is 6) is even, so we can use the special quadratic formula which states that when ax² + bx + c = 0 and b is even, x = (-b' ± √(b'² - ac)) / a where b' = b / 2. In this case, a = 1, b' = 3 and c = 7 so:
x = (-3 ± √(3² - 1 * 7)) / 1 = -3 ± √2
Answer:
f(4) = 3
x = -1
Step-by-step explanation:
Line graphed shows a linear function.
Since this line passes through two points (4, 3) and (-1, 4)
Let the function is,
f(x) = mx + b
where 'm' = slope of the line
b = y-intercept of the line
Slope 'm' = 
= 
= 
f(x) = 
Since a point (4, 3) lies on the line,
f(4) = 
3 = 
b = 3 + 0.8
b = 3.8
Therefore, f(x) = -0.2x + 3.8
For x = 4
f(4) = -0.2(4) + 3.8
= -0.8 + 3.8
= 3.0
For f(x) = 4
4 = -0.2x + 3.8
0.2x = 3.8 - 4
x = 
x = -1
It can be separated into 10 * 3 * 6 and 4 * 3 * 6
the answer would be B<span />