Answer:
The answer is No Solutions
Step-by-step explanation:
Since this is absolute value, we know the answer has to be positive, because distance has to be positive. We see it is negative, and that cannot be, so the answer is no solutions.
3 and what?
if it is 3 and 5 than the answer would be 15
Answer:
The domain is 
The range is 
Step-by-step explanation:
we have
<em>Find the domain</em>
Remember that
The domain of a function is the set of all possible values of x
we know that the radicand of the function must be greater than or equal to zero
so
solve for x
therefore
The domain is
<em>Find the range</em>
Remember that
The range of a function is the complete set of all possible resulting values of y, after we have substituted the domain.
For x=7
The value of y is equal to
so
The solution for y is the interval [1,∞)
therefore
The range is
Answer:
The pairs are (13,15) and (-15,-13).
Step-by-step explanation:
If n is an odd integer, the very next odd integer will be n+2.
n+1 is even (so we aren't using this number)
The sum of the squares of (n) and (n+2) is 394.
This means
(n)^2+(n+2)^2=394
n^2+(n+2)(n+2)=394
n^2+n^2+4n+4=394 since (a+b)(a+b)=a^2+2ab+b^2
Combine like terms:
2n^2+4n+4=394
Subtract 394 on both sides:
2n^2+4n-390=0
Divide both sides by 2:
n^2+2n-195=0
Now we need to find two numbers that multiply to be -195 and add up to be 2.
15 and -13 since 15(-13)=-195 and 15+(-13)=2
So the factored form is
(n+15)(n-13)=0
This means we have n+15=0 and n-13=0 to solve.
n+15=0
Subtract 15 on both sides:
n=-15
n-13=0
Add 13 on both sides:
n=13
So if n=13 , then n+2=15.
If n=-15, then n+2=-13.
Let's check both results
(n,n+2)=(13,15)
13^2+15^2=169+225=394. So (13,15) looks good!
(n,n+2)=(-15,-13)
(-15)^2+(-13)^2=225+169=394. So (-15,-13) looks good!
Answer:
No, because the professor’s question had 3 possible answers
