All categories

3 years ago

What is 3log2 x-(log2 3-log2(x+4)) written as a single logarithm?

Mathematics

2 answers:

Art [367]3 years ago

5 0

Answer:

the answer is c on edge

Step-by-step explanation:

it's the closest one so

log2 (x^3/3)/x+4

which is c

zloy xaker [14]3 years ago

3 0

Answer:
log₂( $\frac{x^2(x+4)}{3}$ )

Explanation:
Before we begin, remember the following:
logₐ(x) - logₐ(y) = logₐ( $\frac{x}{y}$ )
alog(x) = log(xᵃ)

Now, for the given we have:
3 log₂(x) - (log₂3 - log₂(x+4))
log₂(x²) - log₂( $\frac{3}{x+4}$ )

log₂( $\frac{x^2}{ \frac{3}{x+4} }$ ) = log₂( $\frac{x^2(x+4)}{3}$ )

Hope this helps :)

You might be interested in

Class of 50 students dressed up 38% have white shirts. How many are wearing white shirts?

shutvik [7]

Step-by-step explanation:

☥ $\underline{ \underline{ \text{Given} }}:$

Total number of students = 50
Percentage of students who are wearing white shirts = 38 %

☥ $\underline{ \underline {\sf{To \: find} }}:$

Total number of students who are wearing white shirts

☥ $\underline{ \underline{ \sf{Solution} }} :$

⟹ $\sf{38\% \: of \: 50} = \frac{38}{100} \times 50 = \boxed{ \sf{19}}$

$\red{ \boxed{ \boxed{ \tt{⟿ \: Our \: final \: answer : 19}}}}$

Hope I helped ! ♡

Have a wonderful day / night ツ

▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁

3 0

2 years ago

Find the Taylor series for f(x) centered at the given value of a. [Assume that f has a power series expansion. Do not show that

juin [17]

Answer:

The Taylor series of f(x) around the point a, can be written as:

$f(x) = f(a) + \frac{df}{dx}(a)*(x -a) + (1/2!)\frac{d^2f}{dx^2}(a)*(x - a)^2 + .....$

Here we have:

f(x) = 4*cos(x)

a = 7*pi

then, let's calculate each part:

f(a) = 4*cos(7*pi) = -4

df/dx = -4*sin(x)

(df/dx)(a) = -4*sin(7*pi) = 0

(d^2f)/(dx^2) = -4*cos(x)

(d^2f)/(dx^2)(a) = -4*cos(7*pi) = 4

Here we already can see two things:

the odd derivatives will have a sin(x) function that is zero when evaluated in x = 7*pi, and we also can see that the sign will alternate between consecutive terms.

so we only will work with the even powers of the series:

f(x) = -4 + (1/2!)*4*(x - 7*pi)^2 - (1/4!)*4*(x - 7*pi)^4 + ....

So we can write it as:

f(x) = ∑fₙ

Such that the n-th term can written as:

$fn = (-1)^{2n + 1}*4*(x - 7*pi)^{2n}$