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serg [7]
3 years ago
11

Breakout room#5 code?

Mathematics
1 answer:
slavikrds [6]3 years ago
8 0

Answer:

what do you mean

Step-by-step explanation:

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Solve: 12 dogs decreased by 25% step by step pls.
Annette [7]
Decreased by 25%
find 25% of 12 and decrease 12 by it

percent means parts out of 100
25%=25/100=1/4
'of' means multiply
25% of 12=1/4 times 12=3

decrease 12 by 3
12-3=9

answer is 9
8 0
3 years ago
Read 2 more answers
Need help fast, being timed!!
tamaranim1 [39]

Answer:

Mr. Roland’s class was more successful because his class’s lower quartile was the same as Mrs. Cai’s class’s upper quartile.

Step-by-step explanation:

From given scatter plot, we see that upper quartile of Mrs. Cai's class = 4

lower quartile of Mr. Roland’s class = 4

Both are equal so that means.

That means Mr. Roland’s class was more successful because his class’s lower quartile was the same as Mrs. Cai’s class’s upper quartile.


Hence last choice is correct.

4 0
3 years ago
Thomas bought several paintbrushes for $4 each. He paid with a $20 bill. The expression 20 – 4n is used to determine how much ch
Tresset [83]

Answer:

the variable n represents how many of the product thomas bought

Step-by-step explanation:

20 dollars is the initial amount of money, and for every paintbrush, you have to subtract 4 dollars from thomas's initial amount, and the result of the subtraction is the amount of change he will recieve.

4 0
3 years ago
Find the distance between each pair of points. Round to the nearest tenth<br> (-2,2) (5,2)
bija089 [108]

Answer:

Distance = 7

Step-by-step explanation:

d= \sqrt{(x_2-x_1)^2+(y_2-y_1)^2} \\d= \sqrt{(5-(-2))^2+(2-2)^2} \\d= \sqrt{(7)^2+(0)^2} \\d= \sqrt{49+0} \\d= \sqrt{49}\\ d= 7

6 0
3 years ago
To find the measure of ∠A in ∆ABC, use the___(Pythagorean Theorem, Law of Sines, Law of Cosines). To find the length of side HI
nadya68 [22]

<u>Part 1) </u>To find the measure of ∠A in ∆ABC, use

we know that

In the triangle ABC

Applying the law of sines

\frac{a}{sin\ A}=\frac{b}{sin\ B}=\frac{c}{sin\ C}

in this problem we have

\frac{a}{sin\ A}=\frac{b}{sin\ theta}\\ \\a*sin\ theta=b*sin\ A\\ \\ sin\ A=\frac{a*sin\ theta}{b} \\ \\ A=arc\ sin (\frac{a*sin\ theta}{b})

therefore

<u>the answer  Part 1) is</u>

Law of Sines

<u>Part 2) </u>To find the length of side HI in ∆HIG, use

we know that

In the triangle HIG

Applying the law of cosines

g^{2}=h^{2}+i^{2}-2*h*i*cos\ G

In this problem we have

g=HI

G=angle Beta

substitute

HI^{2}=h^{2}+i^{2}-2*h*i*cos\ Beta

HI=\sqrt{h^{2}+i^{2}-2*h*i*cos\ Beta}

therefore

<u>the answer Part 2) is</u>

Law of Cosines

3 0
2 years ago
Read 2 more answers
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