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Solnce55 [7]
3 years ago
9

The weight of an organ in adult males has a​ bell-shaped distribution with a mean of 325 grams and a standard deviation of 25 gr

ams. Use the empirical rule to determine the following. ​(a) About 68​% of organs will be between what​ weights? ​(b) What percentage of organs weighs between 275 grams and 375 ​grams? ​(c) What percentage of organs weighs less than 275 grams or more than 375 ​grams? ​(d) What percentage of organs weighs between 300 grams and 400 ​grams?

Mathematics
1 answer:
vampirchik [111]3 years ago
5 0

Answer:

(a) between 300 grams and 350 grams  (b) 95%  (c) 5%  (d) 83.85%

Step-by-step explanation:

We have that \mu = 325 grams and \sigma = 25 grams. Let's compute the following figures to use the empirical rule

\mu + \sigma  = 325 + 25    = 350  

\mu + 2\sigma = 325 + 2(25) = 375  

\mu + 3\sigma = 325 + 3(25) = 400  

\mu - \sigma  = 325 - 25    = 300  

\mu - 2\sigma = 325 - 2(25) = 275  

\mu - 3\sigma = 325 - 3(25) = 250  

using the image below that was made it with help of the empirical rule we find the next figures

(a) About 68% of organs will be between 300 grams and 350 grams

(b) 95% of organs weights between 275 grams and 375 grams

(c) 5% of organs weights less than 275 grams or more than 375 grams

(d) 83.85% of organs weights between 300 grams and 400 grams

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Um técnico em eletricidade recebeu um molho que continha 12 chaves não identificadas pra abrir a porta de um quarto de hotel e e
77julia77 [94]

Answer:

Step-by-step explanation:

Dado que:

Um técnico em eletricidade recebeu um pacote que continha 12 chaves não identificadas, a probabilidade de que ele acertasse na primeira vez será:

= número de ensaios / número total de ensaios disponíveis

O técnico eletricista tem apenas uma tentativa

uma vez que existem 12 chaves não identificadas, o número total de testes disponíveis 12

∴

= 1/12

= 0.0833

= 0.0833 × 100

= 8.33%

7 0
3 years ago
Rewrite 1/100,000,000 as a power of 10
yarga [219]
1/100,000,000 , note that 100,000,000 = 10⁸ , then:

1/100,000,000  = 1/10⁸
Remember that 1/aⁿ  = a⁻ⁿ

Hence 1/100,000,000 = 1/10⁸ = 10⁻⁸

3 0
3 years ago
Read 2 more answers
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AleksandrR [38]
I think it would be B hope it helps
5 0
4 years ago
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use the formulas for lowering powers to rewrite the expression in terms of the first power of cosine cos^4
Firdavs [7]

The expression cos⁴ θ in terms of the first power of cosine is <u>[ 3 + 2cos 2θ + cos 4θ]/8.</u>

The power-reducing formula, for cosine, is,

cos² θ = (1/2)[1 + cos 2θ].

In the question, we are asked to use the formulas for lowering powers to rewrite the expression in terms of the first power of cosine cos⁴ θ.

We can do it as follows:

cos⁴ θ

= (cos² θ)²

= {(1/2)[1 + cos 2θ]}²

= (1/4)[1 + cos 2θ]²

= (1/4)(1 + 2cos 2θ + cos² 2θ] {Using (a + b)² = a² + 2ab + b²}

= 1/4 + (1/2)cos 2θ + (1/4)(cos ² 2θ)

= 1/4 + (1/2)cos 2θ + (1/4)(1/2)[1 + cos 4θ]

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= 3/8 + cos 2θ/4 + cos 4θ/8

= [ 3 + 2cos 2θ + cos 4θ]/8.

Thus, the expression cos⁴ θ in terms of the first power of cosine is <u>[ 3 + 2cos 2θ + cos 4θ]/8</u>.

Learn more about reducing trigonometric powers at

brainly.com/question/15202536

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5 0
2 years ago
Help please ............
Crank

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