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Anastaziya [24]

4 years ago

12

Please help!!! Look at the attachment

1 answer:

8090 [49]4 years ago

5 0

Option D is the correct answer

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3 ^ x + 1 equals 243

arlik [135]

3^x+1=243 Answer- x=4

6 0

4 years ago

What is the solution to the equation below?<br> √2x divided by √x-2 =2

natka813 [3]

Answer:

C. X = 4

Step-by-step explanation:

3 0

3 years ago

Element X decays radioactively with a half life of 11 minutes. If there are 870 grams of Element X, how long, to the nearest ten

serg [7]

Answer:

It would take 27.5 minutes the element to decay to 154 grams.

Step-by-step explanation:

The decay equation:

$\frac {dN}{dt}\propto -N$

$\Rightarrow \R\frac {dN}{dt}=-\lambda N$

$\Rightarrow \frac {dN}N=-\lambda dt$

Integrating both sides

$\Rightarrow \int \frac {dN}N=\int-\lambda dt$

$\Rightarrow ln|N|=-\lambda t+c$

When t=0, N= $N_0$ = initial amount

$ln|N_0|=-\lambda .0+c$

$\Rightarrow c=ln|N_0|$

$ln|N|=-\lambda t+ln|N_0|$

$\Rightarrow ln|N|-ln|N_0|=-\lambda t$

$\Rightarrow ln|\frac{N}{N_0}|=-\lambda t$

Decay equation:

$ln|\frac{N}{N_0}|=-\lambda t$

Given that, the half life of of element X is 11 minutes.

For half life, $N=\frac12 N_0$ , t= 11 min.

$ln|\frac{N}{N_0}|=-\lambda t$

$\Rightarrow ln|\frac{\frac12N_0}{N_0}|=-\lambda . 11$

$\Rightarrow ln|\frac12}|=-\lambda . 11$

$\Rightarrow -\lambda . 11=ln|\frac12}|$

$\Rightarrow \lambda =\frac{ln|\frac12|}{-11}$

$\Rightarrow \lambda =\frac{ln|2|}{11}$ [ $ln|\frac12|=ln|1|-ln|2|=-ln|2|$ , since ln|1|=0]

N=154 grams, $N_0$ = 870 grams, t=?

$ln|\frac{N}{N_0}|=-\lambda t$

$\Rightarrow ln|\frac{154}{870}|=-\frac{ln|2|}{11}.t$

$\Rightarrow t= \frac{ln|\frac{154}{870}|\times 11}{-ln|2|}$

=27.5 minutes

It would take 27.5 minutes the element to decay to 154 grams.

5 0

3 years ago

Find the value of x in the triangle shown below.<br> 8<br> 2<br> Answer?

Lyrx [107]

The answer is -2 because I already took this

6 0

3 years ago

Customer account numbers for a certain company consists of 3 letters followed by 5 numbers how many different account numbers ar

Arturiano [62]

Answer:

1,757,600,000

Step-by-step explanation:

company consists of 3 letters followed by 5 numbers how many different account numbers are possible if repetitions of letters and digits are allowed.

We have 26 lettrs and 10 digits

So, the possible out comes for each one of the letters = 26

And the possible out comes for each one of the numbers = 10

∵ repetitions of letters and digits are allowed.

So, the possible accounts are = 26³ * 10⁵ = <u>1,757,600,000</u>

5 0

4 years ago