<h2>
Answer:</h2><h2>
<em>Root</em><em> </em><em>is</em><em> </em><em>not</em><em> </em><em>the</em><em> </em><em>major</em><em> </em><em>parts</em><em> </em><em>of</em><em> </em><em>bulb</em><em>.</em></h2>
Explanation:
<em>h</em><em>o</em><em>p</em><em>e</em><em> </em><em>i</em><em>t</em><em> </em><em>h</em><em>e</em><em>l</em><em>p</em><em> </em><em>y</em><em>o</em><em>u</em><em />
The first option for 1 and the second option for 2
New disease that affects the younger of a population, shortage of availability of food, new competitor for food, new predator of jaguars (though there arent many of those)
Answer:
1) Organisms in this domain can be unicellular or multicellular - Eukarya
2) Organisms in this domain are unicellular and are often found in extreme environments - Archaea
3) Organisms in this domain have cells that contain a nucleus - Eukarya
Explanation:
All living organisms were classified into a large group consisting of three types of organisms called DOMAIN. It is the highest taxonomic rank of organisms. The three domains that life was classified into are: Archaea, Bacteria and Eukarya.
The domain Archaea contains organisms that are unicellular and prokaryotic i.e. they do not have a membrane-bound nucleus. The organisms in this domain are characterized by their ability to survive in harsh environmental conditions e.g hot temperatures etc
The domain Bacteria also consists of unicellular and prokaryotic organisms. They contain cell walls in their cells made up of peptidoglycan unlike domain Archaea and Eukarya.
The domain Eukarya consists of organisms that are both unicellular and multicellular and strictly eukaryotic i.e. possess a membrane bound nucleus that houses their genetic material. They are divided into Kingdoms: Protista, Plantae, Animalia and Fungi.
Answer:The ratio of the concentrations of 
and 
when the buffer has a pH of 7.02 is 0.69
Explanation:
The dissociation constant for formic acid = 
Concentration of HA= 0.5 mM
Concentration of = 0.1 mM
pH = 6.16
First we have to calculate the value of 
.
Using Henderson Hesselbach equation :
![pH=pK_a+\log \frac{[A^-}{[HA]}](https://tex.z-dn.net/?f=pH%3DpK_a%2B%5Clog%20%5Cfrac%7B%5BA%5E-%7D%7B%5BHA%5D%7D)
Now put all the given values in this expression, we get:
![6.16=pK_a+\log (\frac{[0.1]}{0.5})](https://tex.z-dn.net/?f=6.16%3DpK_a%2B%5Clog%20%28%5Cfrac%7B%5B0.1%5D%7D%7B0.5%7D%29)
To calculate the ratio of the concentrations of and when the buffer has a pH of 7.02.
Using Henderson Hesselbach equation :
![7.02=6.86+\log \frac{[A^-]}{[HA]}](https://tex.z-dn.net/?f=7.02%3D6.86%2B%5Clog%20%5Cfrac%7B%5BA%5E-%5D%7D%7B%5BHA%5D%7D)
![\frac{[A^-]}{[HA]}=1.44](https://tex.z-dn.net/?f=%5Cfrac%7B%5BA%5E-%5D%7D%7B%5BHA%5D%7D%3D1.44)
![\frac{[HA]}{[A^-]}=0.69](https://tex.z-dn.net/?f=%5Cfrac%7B%5BHA%5D%7D%7B%5BA%5E-%5D%7D%3D0.69)
Thus the ratio of the concentrations of and when the buffer has a pH of 7.02 is 0.69
