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taurus [48]
3 years ago
12

I have 5 questions. Please help.

Mathematics
1 answer:
Lady bird [3.3K]3 years ago
3 0

Answer:

1. 1

2. 5/8

3. 3/4

4. 7/8

5. 5/8

Step-by-step explanation:

1. The denominators are the same, so just add the top numbers (the numerator), 1/7 + 6/7 = 7/7, which is 1.

2. The denominators are the same, so just add the top numbers (the numerator), 7/16+3/16=10/16. 10/16 can be divided by 2 to get 5/8.

3. 1/6=2/12. So, the new problem is 2/12+7/12. Add the numbers, and you get 9/12. Divide the top and bottom by 3, and your answer is 3/4.

4. 3/4=6/8. The new problem is 6/8+1/8. This is 7/8.

5. 1/4=2/8. The new problem is 2/8+3/8. 2+3 is 5, so your answer is 5/8.

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The drawing below shows a row of grocery carts that have been " nested" together. The carts are each 32in. Long. Each cart after
creativ13 [48]

Answer:

Length of Row of n cart  = 11(n-1)+32 inches

The length of row for 20 nested carts will be = 11(20-1) +32 = 209 + 32 =241 inches.

Step-by-step explanation:

The length of one cart is 32 inches.

When you nest two cart, the length of the second cart will be 11 inches, so the total length of two nested cart will be 43 inches. From the this statements we can derive the following.

Length of Row of 1 cart   = (1-1)*11+ 32 =32 inches

Length of Row of 2 cart   =(2- 1)*11+32 = 43 inches

Length of Row of 3 cart   = (3-1)*11 +32 = 54 inches

Length of Row of 4 cart  = (4-1)*11 + 32 = 65 inches

Length of Row of 5 cart  = (5-1)*11+32 = 76 inches

Length of Row of 6 cart  = (6-1)*11+32 = 87 inches

Length of Row of 7 cart  = (7-1)*11+32 = 98 inches

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Length of Row of 9 cart  = (9-1)*11+32 = 120 inches

Length of Row of 10 cart  = (10-1)*11+32 = 131 inches

Length of Row of n cart  = (n-1)*11 + 32 =11(n-1)+32 inches

The relationship between the length of the row and the number of carts is given as Length of Row of n cart  = 11(n-1)+32 inches

where n is the number of carts

The length of row for 20 nested carts will be = 11(20-1) +32 = 209 + 32 =241 inches.

4 0
3 years ago
Solve each triangle for the missing values shown. Show all work necessary. Use exact values
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3)

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Now, use Pythagoras theorem to find x

x^2+y^2=10^2 \\\\ \to x^2+5^2=10^2 \\\\ \to x^2+25=100 \\\\ \to x^2 = 100-25 \\\\ \to x^2= 75 \\\\ \to x= \sqrt{75} \\\\ \bf 5 \sqrt{3}

Similarly,

4)

Sin 45°= \frac{1}{\sqrt{2}} = \frac{Opposite} {Hypotenuse} =\frac{2 \sqrt{2}} {a} \\\\ a= 2 \sqrt{2} \times \sqrt{2} \\\\ a=4

Now, use Pythagoras theorem to find b

b^2+(2 \sqrt{2}) ^2=a^2 \\\\ \to b^2+8=4^2 \\\\ \to b^2=16-8  \\\\ \to b^2 = 8\\\\ \to b= \sqrt{8} \\\\ \bf b=2 \sqrt{2}

You can solve all of them in a similar way.

: )

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Could someone please explain how to solve
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