Answer:
The equation of the line with slope m = 2 and passing through the point (1, 1) will be:
Step-by-step explanation:
We know that the point-slope form of the line equation is
where
- m is the slope of the line
The formula is termed as the point-slope form of the line equation because if we know one point on a certain line and the slope of that line, then we can easily get the line equation with this formula and, hence, determine all other points on the line.
For example, if we are given the point (1, 1) and slope m = 2
Then substituting the values m = 2 and the point (1, 2)
Therefore, the equation of the line with slope m = 2 and passing through the point (1, 1) will be:
From the given information we can write the equation:
-16t^2 +96t + 4 = 112
-16t^2 + 96t + 4 - 112 = 0
-16t^2 + 96t - 108 = 0
simplify, change the signs, divide by -4
4t^2 - 24t + 27 = 0
You can use the qudratic formula but this will factor to
(2t-3)(2t-9) = 0
Two solutions
t = 3/2
t = 1.5 seconds at 112 ft on the way up
and
t = 9/2
t = 4.5 seconds at 112 ft on the way back down
Graphically, (green line is 112 ft)
Looking at the given points on the right side from (0,2) to (1,6) for 1 increase in X ( 1-0=1) the Y value increases by 3 ( 6/2 = 3)
This same increase happens for th other two points: 18/6 = 3
54 / 18 = 3
The rate of increase is 3.
