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3 years ago

Suppose we have a bag with 10 slips of paper in it. Eight of these have a 2 on them and the other two have a 4 on them.

Mathematics

2 answers:

irga5000 [103]3 years ago

7 0

Answer:

The expected value of one draw is the average value of these 10 slips of paper which is:

24 / 10 = 2.4

Step-by-step explanation:

We have a bag with 10 slips of paper in it. 8 slips of paper each has a 2 on them; 2 slips of paper each has a 4 on them.

The total value of all the slips when added together is:

= (8)(2) + (2)(4)

= 16 + 8 = 24

The expected value of one draw is the average value of these 10 slips of paper which is:

24 / 10 = 2.4 ....

Sergio [31]3 years ago

5 0

Answer:

21/5

Step-by-step explanation:

3 * 8/10 + 9 *2/10

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Genetic Defects Data indicate that a particular genetic defect occurs in of every children. The records of a medical clinic show

Dovator [93]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The probability that there exist 60 or more defected children is $P(x \ge 60)=0.0901$

Looking at the value for this probability we see that it is not so small to the point that the observation of this kind would be a rare occurrence

Step-by-step explanation:

From the question we are told that

in every 1000 children a particular genetic defect occurs to 1

The number of sample selected is $n= 50,000$

The probability of observing the defect is mathematically evaluated as

$p = \frac{1}{1000}$

$= 0.001$

The probability of not observing the defect is mathematically evaluated as

$q = 1-p$

$= 1-0.001$

$= 0.999$

The mean of this probability is mathematically represented as

$\mu = np$

Substituting values

$\mu = 50000*0.001$

$= 50$

The standard deviation of this probability is mathematically represented as

$\sigma = \sqrt{npq}$

Substituting values

$= \sqrt{50000 * 0.001 * 0.999}$

$= \sqrt{49.95}$

$= 7.07$

the probability of detecting $x \ge60$ defects can be represented in as normal distribution like

$P(x \ge 60)$

in standardizing the normal distribution the normal area used to approximate $P(x \ge 60)$ is the right of 59.5 instead of 60 because x= 60 is part of the observation

The z -score is obtained mathematically as

$z = \frac{x-\mu }{\sigma }$

$= \frac{59.5 - 50 }{7.07}$

$=1.34$

The area to the left of z = 1.35 on the standardized normal distribution curve is 0.9099 obtained from the z-table shown z value to the left of the standardized normal curve

Note: We are looking for the area to the right i.e 60 or more

The total area under the curve is 1

$P(x \ge 60) \approx P(z > 1.34)$

$= 1-P(z \le 1.34)$

$=1-0.9099$

$=0.0901$

3 0

2 years ago

Suppose a parabola has vertex (6,5) and also passes through the point (7,7). Write the equation of the parabola in vertex form.

jek_recluse [69]

Answer:

Choice B: $y = 2\, (x - 6)^{2} + 5$ .

Step-by-step explanation:

For a parabola with vertex $(h,\, k)$ , the vertex form equation of that parabola in would be:

$\text{$y = a\, (x - h)^{2} + k$ for some constant $a$}$ .

In this question, the vertex is $(6,\, 5)$ , such that $h = 6$ and $k = 5$ . There would exist a constant $a$ such that the equation of this parabola would be:

$y = a\, (x - 6)^{2} + 5$ .

The next step is to find the value of the constant $a$ .

Given that this parabola includes the point $(7,\, 7)$ , $x = 7$ and $y = 7$ would need to satisfy the equation of this parabola, $y = a\, (x - 6)^{2} + 5$ .

Substitute these two values into the equation for this parabola:

$7 = (7 - 6)^{2}\, a + 5$ .

Solve this equation for $a$ :

$7 = a + 5$ .

$a = 2$ .

Hence, the equation of this parabola would be:

$y = 2\, (x - 6)^{2} + 5$ .

4 0

2 years ago

Dianne drew a triangle with coordinates (1,3), (3,2) and (4,2) she drew an image of the triangle with coordinates (21,3) ,(23,2)

Bond [772]

Answer:

ttrhrtherhhhtrhtr

Step-by-step explanation:

6 0

3 years ago

Tyrod needs at least $820 to buy the computer he wants. He has already saved $330. He earns $50 per lawn that he cuts. What is t

Ksju [112]

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The equation representing the given statement is ~

$50x + 330 \geqslant 820$

The least number of lawns that he can cut and buy the computer is 10 lawns ~

$\large \boxed{ \mathfrak{Step\:\: By\:\:Step\:\:Explanation}}$

Total savings should be greater or equal to $ 820 in order to buy the computer,

And his total savinga is equal to ~

Money he saved + money got from cutting lawns.

let's assume the lawns cut by Tyrod be x,

Money earned by cutting lawns is equal to

total number of lawns cut × $50

total savings is equal to ~

330 + 50x

hence,

$50x + 330 \geqslant 820$

by solving for " x (number of lawns cut) " we get ~

$50x \geqslant 820 - 330$

$50x \geqslant 490$

$x \geqslant 490 \div 50$

$x \geqslant 9.8$

Hence, the least number of lawns he has to cut is the number that is greater than 9.8, which is

$10$

6 0

2 years ago

For geometry:(<br><br> will give brainist to the correct answer!!!

Strike441 [17]

Answer:

y = ⅔x - 5

Step-by-step explanation:

To write the equation, find the slope (m), to enable you write the equation of the line in point-slope form given a point, (-3, -7) that the line passes through.

Since the line is parallel to 2x - 3y = 24,, it would have the same slope (m) value.

Rewrite 2x - 3y = 24 in slope-intercept form.

Thus:

2x - 3y = 24

-3y = -2x + 24

y = ⅔x - 12

The slope of 2x - 3y = 24 is ⅔. Therefore, the line that is parallel to 2x - 3y = 24 is also ⅔.

To write the equation of the line, substitute (a, b) = (-3, -7) and m = ⅔ into y - b = m(x - a)

Thus:

y - (-7) = ⅔(x - (-3))

y + 7 = ⅔(x + 3)

y + 7 = ⅔x + 2

y = ⅔x + 2 - 7

y = ⅔x - 5

5 0

3 years ago