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tekilochka [14]
3 years ago
15

Solve the inequality, -3/2<3x

Mathematics
1 answer:
MArishka [77]3 years ago
5 0

For this case we must resolve the following inequality:

- \frac {3} {2}

So, if we divide by 3 on both sides of the equation we have:

\frac {- \frac {3} {2}} {3}

Thus, the solution is given by all the values of "x" greater than - \frac {1} {2}

Answer:

The solution to inequality is:

(- \frac {1} {2};∞)

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The radius of the Outer circle (with r₂) is 6 and the radius of the inner circle (with r₁) is 2. When objects are similar, they have a proportional relationship. If we take the outer circle and squeeze by one third, we get a radius of 6 x 1/3 = 2. On the other hand, if we start with the inner circle and stretch it by 3, we get a radius of 2 x 3 = 6.


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5 0
3 years ago
4.1&lt;7 as a fraction. pls workout and ill mark you brainliest
labwork [276]

Answer:

4/7

Step-by-step explanation:

hope this helps

3 0
3 years ago
Simplify
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I got number 1,2,3 only

4 0
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NeX [460]

Answer:

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I know it's a lot, the hair, the bod

When you're staring at a demigod

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Hey, it's okay, it's okay

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Look at that mean mini Maui just tikkity tappin'

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People are clappin', hearing me rappin'

And bring the chorus back in

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Step-by-step explanation:

4 0
3 years ago
5. Find the point P along the directed line segment from X(-3, 3) to Y(6,-3) that divides
ASHA 777 [7]
Consider point P(x,y) such that P, X and Y are collinear,

As vectors

XP = XO + OZ where O(0,0)
XP = OZ - OX
XP= (x,y) - (-3,3)
XP = (x+3, y-3)

Similarly,

PY = (6-x, -3-y)

But XP= 2^PY

[x+3, y-3] = [2(6-x), 2(-3-y)]

Given both vectors are equal, as they go in the same direction, Solve for x and y accordingly:

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y = -1

Therefore, P(3,-1)

6 0
3 years ago
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