How do you solve logarithmic equations such as log(2x)= -1 or 3log(2)+log(x)= 3?
1 answer:
Remember some simle log rules
loga+logb=log(ab)
xloga=loga^x
means 
also, if no base is stated, assume base 10
so
log(2x)=-1 is base 10 and translates to
10^-1=2x
1/10=2x
divide both sides by 2 aka times 1/2
1/20=x
3log(2)+log(x)=3
log(2^3)+log(x)=3
log(8)+log(x)=3
log(8x)=3
base 10
10^3=8x
1000=8x
divide both sides by 8
x=125
loga+logb=log(ab)
xloga=loga^x
also, if no base is stated, assume base 10
so
log(2x)=-1 is base 10 and translates to
10^-1=2x
1/10=2x
divide both sides by 2 aka times 1/2
1/20=x
3log(2)+log(x)=3
log(2^3)+log(x)=3
log(8)+log(x)=3
log(8x)=3
base 10
10^3=8x
1000=8x
divide both sides by 8
x=125
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Option B. 55° is the correct answer
Step-by-step explanation:
"The sum of interior angles of a triangle is always 180°"
Given
m∠A=(3x+1)°
m∠B=(2x-1)°
m∠C = 40°
We know that
m∠A+m∠B+m∠C=180°
Putting the values of angles
Subtracting 40 from both sides
Dividing both sides by 5
We have to find Angle B,
So
m∠B = 2x-1 = 2(28)-1 = 56-1 = 55°
Hence,
m∠B=55°
Option B. 55° is the correct answer
Keywords: Triangle, Interior angles
Learn more about triangles at:
#learnwithBrainly