<span>dividend x3 - 11x2 + 16x + 84
- divisor * x2 x3 - 7x2
remainder - 4x2 + 16x + 84
- divisor * -4x1 - 4x2 + 28x
remainder - 12x + 84
- divisor * -12x0 - 12x + 84
remainder 0
Quotient : x2-4x-12 Remainder: 0
Step-1 : Multiply the coefficient of the first term by the constant 1 • -12 = -12
Step-2 : Find two factors of -12 whose sum equals the coefficient of the middle term, which is -4 .
-12 + 1 = -11
-6 + 2 = -4 That's it
Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -6 and 2
x2 - 6x + 2x - 12
Step-4 : Add up the first 2 terms, pulling out like factors :
x • (x-6)
Add up the last 2 terms, pulling out common factors :
2 • (x-6)
Step-5 : Add up the four terms of step 4 :
(x+2) • (x-6)
Which is the desired factorization
Final result :
(x + 2) • (x - 6) • (x - 7)</span>
1. (2r + 9)(2r-9) = 4r^2 -81
+ (2r - 9)^2 = 4r^2 - 36r + 81
= 8r^2 - 36r
2. 12 - 5 [ a^2 + a - 1 ] + 5a
= 12 - 5a^2 - 5a + 5 +5a
= 17 - 5a^2
x^3 + 3x^2 + 6x + 18
______
3. x-3/ x^4 + 7
- ( x^4 - 3x^3)
----------------
3x^3 + 7
- (3x^3 - 6x^2)
-------------------
6x^2 + 7
- (6x^2 - 18x)
-------------------
18x + 7
- (18x - 54)
--------------
7 + 54 = R = 61
welp That's What I get
Answer:
m∠LON = m∠HKJ
Step-by-step explanation:
. m∠LOM = m∠JKI; m∠MON = m∠IKH 1.
2. m∠LOM + m∠MON = m∠JKI + 2.
m∠MON
3. m∠LOM + m∠MON = m∠JKI + 3.
m∠IKH
4. m∠LOM + m∠MON = m∠LON; 4.
m∠JKI + m∠IKH = m∠HKJ
5. m∠LON = m∠HKJ 5.
Hey!
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Writing scientific notation in numeral is solving for the equation.
Multiply 10 to 6.4 seven times.
6.4 x 10 = 64
64 x 10 = 640
640 x 10 = 6,400
6,400 x 10 = 64,000
64,000 x 10 = 640,000
640,000 x 10 = 6,400,000
6,400,000 x 10 = 64,000,000
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Hope This Helped! Good Luck!
Answer:
b
Step-by-step explanation:
just believe me and don't forget to mark brainliest
