Switch where the x and y are, then solve for y. f(x) = y.
x = 3y^2 + 6
x-6 = 3y^2
(x-6)/3 = y^2
f^-1(x) = y = sqrt((x-6)/3)
The probability that his number will be 4 is one in eleven, or 1/11.
The absolute value inequality can be decomposed into two simpler ones.
x < 0
x > -8
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Which two inequalities can be used?</h3>
Here we start with the inequality:
3|x + 4| - 5 < 7
First we need to isolate the absolute value part:
3|x + 4| < 7 + 5
|x + 4| < (7 + 5)/3
|x + 4| < 12/3
|x + 4| < 4
The absolute value inequality can now be decomposed into two simpler ones:
x + 4 < 4
x + 4 > - 4
Solving both of these we get:
x < 4 - 4
x > -4 - 4
x < 0
x > -8
These are the two inequalities.
Learn more about inequalities:
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Answer:
when h(x) = 0, x = 7/3
Step-by-step explanation:
0 = 3x - 7
7 = 3x
7/3 = x
If you would like to solve 9 5/9 - 6 5/6, you can calculate this using the following steps:
9 5/9 - 6 5/6 = 86/9 - 41/6 = 516/54 - 369/54 = (516 - 369) / 54 = 147/54 = 49/18 = 2 13/18
The correct result would be 2 13/18.
