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3 years ago

Which 2 statements are TRUE about Exponential Functions?

1 answer:

5 0

The true statements are:
The equation has a variable in the exponent position.
The graph has a variable rate of change which causes it to have a curved shape.

These are the defining characteristics of an exponential function.

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Part C

mel-nik [20]

Answer:

Tamara needs to cover a total of 476 square feet.
Tamara will have enough material to cover all four walls.

Step-by-step explanation:

If the room dimensions are 8 1/3 feet by 11 1/2 feet, the perimeter length is ...

P = 2(L+W) = 2(8 1/3 +11 1/2) = 2(19 5/6) = 39 2/3 feet

The area of the walls is the product of this perimeter length and the height of the wall. If that height is 12 feet, then the wall area is ...

A = PH = (39 2/3 ft)(12 ft) = 476 ft²

Tamara needs to cover a total of 476 square feet.

If Tamara orders 480 square feet of material, ...

Tamara will have enough to cover all four walls.

6 0

3 years ago

A student conducts several random surveys to find out the most preferred lunch option. Each survey was of 60 students. No studen

stira [4]

Answer:

is the answer

I think soo

5 0

3 years ago

$239 television 10% discount

kiruha [24]

23.9 is the discount so you gonna round it up so get an whole number the answer is 24

5 0

3 years ago

An 8 ounce mug requires 0.3 cup of hot cocoa mix. How much hot cocoa mix is needed for a 12 ounce mug?

8090 [49]

Answer:

0.45

Step-by-step explanation:

Step 1:

$\frac{8}{0.3} =\frac{12}{x}$

Step 2:

8 · x = 0.3 · 12

8x = 3.6

Last Step: Divide both sides by 8 to isolate the value x

3 0

3 years ago

Calculate two iterations of Newton's Method for the function using the given initial guess. (Round your answers to four decimal

pickupchik [31]

Answer:

The first and second iteration of Newton's Method are 3 and $\frac{11}{6}$ .

Step-by-step explanation:

The Newton's Method is a multi-step numerical method for continuous diffentiable function of the form $f(x) = 0$ based on the following formula:

$x_{i+1} = x_{i} -\frac{f(x_{i})}{f'(x_{i})}$

Where:

$x_{i}$ - i-th Approximation, dimensionless.

$x_{i+1}$ - (i+1)-th Approximation, dimensionless.

$f(x_{i})$ - Function evaluated at i-th Approximation, dimensionless.

$f'(x_{i})$ - First derivative evaluated at (i+1)-th Approximation, dimensionless.

Let be $f(x) = x^{2}-8$ and $f'(x) = 2\cdot x$ , the resultant expression is:

$x_{i+1} = x_{i} -\frac{x_{i}^{2}-8}{2\cdot x_{i}}$

First iteration: ( $x_{1} = 2$ )

$x_{2} = 2-\frac{2^{2}-8}{2\cdot (2)}$

$x_{2} = 2 + \frac{4}{4}$

$x_{2} = 3$

Second iteration: ( $x_{2} = 3$ )

$x_{3} = 3-\frac{3^{2}-8}{2\cdot (3)}$

$x_{3} = 2 - \frac{1}{6}$

$x_{3} = \frac{11}{6}$

7 0

4 years ago