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Lelechka [254]
3 years ago
9

Simplify each algebraic expression.

Mathematics
1 answer:
GREYUIT [131]3 years ago
3 0

Answer:

\huge\boxed{\sf-2x+28}\\\\\huge\boxed{\sf 10x-4}\\\\\huge\boxed{\sf 56-5x}\\\\\huge\boxed{\sf x-13}

Step-by-step explanation:

\sf 2x + 4(7-x)  \\\\Resolving \ Parenthesis\\\\2x + 28-4x \\\\Combining\ like\ terms\\\\2x-4x +28\\\\-2x + 28\\\\\rule[225]{225}{2}

\sf \\12x-(4+2x)\\\\12x-4-2x\\\\Combining \ like \ terms\\\\12x-2x - 4\\\\10x-4 \\\\\rule[22]{225}{2} \\2(10-x)+3(12-x) \\\\Resolving \ Parenthesis\\\\20-2x + 36 -3x\\\\Combining \ like \ terms\\\\20+36 -2x-3x\\\\56 - 5x \\\\\rule[225]{225}{2}

\sf 7(x-1)-6(x+1)\\\\Resolving \ Parethesis\\\\7x-7-6x-6\\\\Combining \ like \ terms\\\\7x-6x-7-6\\\\x - 13\\\\\rule[225]{225}{2}

Hope this helped!

~AnonymousHelper1807

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Answer:

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Step-by-step explanation:

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Where <em>a</em> is some constant.

We can let:
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By substitution:

\displaystyle g(s) = \int_6^s g(t)\, dt

Taking the derivative of both sides results in:
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Hence, by the Fundamental Theorem:

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