Answer:
x = 25 degrees
Step-by-step explanation:
All angles in a triangle should add up to 180 degrees. So to solve for x, set up an equation where all three angles added up equals 180.
180 = 99 + 56 + x
180 = 155 + x
25 = x
The unknown angle is equal to 25 degrees.
Slope = (10 - 5)/(-9 + 15) = 5/6
y = mx + b where m = slope and b = y-intercept
b = y - mx
b = 5 - (5/6) (-15)
b = 5 +12.5
b = 17.5
Equation y = 5/6 x + 17.5
Y-intercept = 17.5
X-intercept when y = 0
So
5/6 x + 17.5 = 0
5/6 x = -17.5
x = (-17.5) (6/5)
x = -21
Answer
Y intercept (0, 17.5 )
X intercept (-21 , 0)
Answer:
- The shaded region is 9.83 cm²
Step-by-step explanation:
<em>Refer to attached diagram with added details.</em>
<h2>Given </h2>
Circle O with:
- OA = OB = OD - radius
- OC = OD = 2 cm
<h2>To find</h2>
<h2>Solution</h2>
Since r = OC + CD, the radius is 4 cm.
Consider right triangles OAC or OBC:
- They have one leg of 2 cm and hypotenuse of 4 cm, so the hypotenuse is twice the short leg.
Recall the property of 30°x60°x90° triangle:
- a : b : c = 1 : √3 : 2, where a- short leg, b- long leg, c- hypotenuse.
It means OC: OA = 1 : 2, so angles AOC and BOC are both 60° as adjacent to short legs.
In order to find the shaded area we need to find the area of sector OADB and subtract the area of triangle OAB.
Area of <u>sector:</u>
- A = π(θ/360)r², where θ- central angle,
- A = π*((mAOC + mBOC)/360)*r²,
- A = π*((60 + 60)/360))(4²) = 16.76 cm².
Area of<u> triangle AO</u>B:
- A = (1/2)*OC*(AC + BC), AC = BC = OC√3 according to the property of 30x60x90 triangle.
- A = (1/2)(2*2√3)*2 = 4√3 = 6.93 cm²
The shaded area is:
- A = 16.76 - 6.93 = 9.83 cm²
The answer would be D if it was 250-6-3n. it wouldnt be A or C because 9 isnt anywhere in the problem and it wouldnt be B because she used 6 peices of paper she didnt just give it to her students
Answer:
The area should be 170
Step-by-step explanation:
L× W =70×10=170