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san4es73 [151]
2 years ago
10

Solve the inequality

Mathematics
1 answer:
Naily [24]2 years ago
8 0

Answer:

16(1/4x-1/2)>24-2x

Use the distributive property on the left side:

4x -8 > 24-2x

Add 2x to each side:

6x -8 > 24

Add 8 to each side:

6x >32

Divide both sides by 6:

x > 32/6 reduces to 16/3

If this is helpful plz mark brainliest

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Find the missing terms in the<br>sequence 27, ? , 23, ? , 19,...<br>good luck​
Vikki [24]
Is it subtract by 2? So I think it would be 27,25,23,21, 19
8 0
3 years ago
Joe can weed the garden twice as fast as his sister Janet. Together they can weed the garden in 2 hours. How long would it take
scoundrel [369]

Answer:

Joe: 3 hrs

Janet: 6hrs

Step-by-step explanation:

joe takes x hours

so in 1 hr he does 1/x of the garden

janet takes 2x hours

so in 1 hr she does 1/(2x) of the garden

In one hour together they do 1/2 of the garden

1/x + 1/(2x) = 1/2

2/(2x) + 1/(2x) = 1/2

3/(2x) = 1/2

Cross multiply

6 = 2x

x = 3

Joe: 3 hrs

Janet: 6hrs

4 0
3 years ago
What is the sum in simplest form for 5/8+2/5
Bogdan [553]
(5/8)+(2/5)= 

so you need a common den so in this case its 40

so we multiply to get 40 like

(5/5)(5/8)+ (2/5)(8/8)=

25/40 + 16/ 40 = 41/40
5 0
3 years ago
The total income from the sale of cheeseburgers was what percent greater in 2004 than in 2003?
sveticcg [70]

\bf \begin{array}{|c|c|c|ll} \cline{1-3} year&quantity&price\\ \cline{1-3} 2003&Q&P\\&&\\ 2004&20\%Q+Q&\\&&\\ &\frac{20}{100}Q+Q&\\&&\\ &1.2Q&\\&&\\ &&10\%P+P\\ &&\frac{10}{100}P+P\\&&\\ &&1.10P\\ \cline{1-3} &&\\ &(1.2Q)&(1.10P)\\ \cline{1-3} \end{array}\qquad \begin{array}{llll} \stackrel{\textit{revenue for 2003}}{(Q)(P)}\implies QP\\\\ \stackrel{\textit{revenue for 2004}}{(1.2Q)(1.10P)}\implies 1.32QP \end{array}

7 0
3 years ago
A recursive rule for an arithmetic sequence is a₁=4;a_n=a_(n−1)−3 .
steposvetlana [31]

The explicit formula of the arithmetic sequence:

a_n=a_1+(n-1)d

d - common difference

We have the recursive formula of an arithmetic sequence:

\left\{\begin{array}{ccc}a_1=4\\a_n=a_{n-1}-3\end{array}\right

Therefore we have:

a_1=4,\ d=-3

Substitute:

a_n=4+(n-1)(-3)=4-3n+3=7-3n

<h3>Answer: aₙ = 7 - 3n</h3>
3 0
3 years ago
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