0.5, 3/16, 5/48 in order from least to greatest

If total advertising expenditures on television advertising declined 4.1% to $141.7 billion in the current year, how much was sp

Vanyuwa [196]

Using proportions, it is found that $147.8 billion was spent on television advertising in the previous year.

$x, in billions, was spent on advertising expenditures on television last year.

This year, the amount declined 4.1%, hence it is 100% - 4.1% = 95.9% of last year's amount, that is, 0.959x.

This year spending's is of 141.7 billion, hence, the equation is:

$0.959x = 141.7$

$x = \frac{141.7}{0.959}$

$x = 147.8$

$147.8 billion was spent on television advertising in the previous year.

To learn more about proportions, you can take a look at brainly.com/question/24372153

4 0

2 years ago

What is 65.5 percent as a decimal

adell [148]

Answer:

65.5/100 = 0.665

Step-by-step explanation:

*Hope this helps*

4 0

2 years ago

Find the indicated root

Sever21 [200]

So you have to put 25 inside the blank box.

look at the attached picture

Hope it will help you

Good luck on your assignment

6 0

3 years ago

Read 2 more answers

A local coupon mailer charges $11 for each of the first three lines of an ad, and $5 for each additional line. What is the price

Tema [17]

: $55

:

Cost first 3 lines: $11 per line
Cost per additional line: $5

We are interested in 5-line ad, we place 3 lines or less, then we have to pay $11 per line in the ad.

Cost 5-lines = number of lines x cost per line

x = 5 x 11

55

3 0

3 years ago

spin [16.1K]

Answer:

$z=\frac{0.18 -0.1}{\sqrt{\frac{0.1(1-0.1)}{100}}}=2.67$

Step-by-step explanation:

1) Data given and notation

n=100 represent the random sample taken

X=18 represent the ounce cups of coffee that were underfilled

$\hat p=\frac{18}{100}=0.18$ estimated proportion of ounce cups of coffee that were underfilled

$p_o=0.1$ is the value that we want to test

$\alpha$ represent the significance level

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

2) Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that the true proportion it's higher than 0.1 or 10%:

Null hypothesis: $p\leq 0.1$

Alternative hypothesis: $p > 0.1$

When we conduct a proportion test we need to use the z statistic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

3) Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.18 -0.1}{\sqrt{\frac{0.1(1-0.1)}{100}}}=2.67$

4) Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level assumed for this case is $\alpha=0.05$ . The next step would be calculate the p value for this test.

Since is a one right tailed test the p value would be:

$p_v =P(Z>2.67)=0.0037$

So the p value obtained was a very low value and using the significance level given $\alpha=0.05$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance thetrue proportion is not significanlty higher than 0.1 or 10% .

5 0

3 years ago