Given that the line passes through two points
(-2,-2) and (x1,y1)
Equation in point slope form is
y-y1 = m(x-x1)
substitute for slope
Hence equation of the line = ![\frac{y2-y1}{x2-x1} =[tex]y-y1 = \frac{-2-y1}{-2-x1}(x-x1)](https://tex.z-dn.net/?f=%5Cfrac%7By2-y1%7D%7Bx2-x1%7D%20%3D%5Btex%5Dy-y1%20%3D%20%5Cfrac%7B-2-y1%7D%7B-2-x1%7D%28x-x1%29)
Since we donot know the value of x1or y1 the equation would contain x1, y1 also as answer.
Answer in point slope form is
![\frac{y2-y1}{x2-x1} =[tex]y-y1 = \frac{-2-y1}{-2-x1}(x-x1)](https://tex.z-dn.net/?f=%5Cfrac%7By2-y1%7D%7Bx2-x1%7D%20%3D%5Btex%5Dy-y1%20%3D%20%5Cfrac%7B-2-y1%7D%7B-2-x1%7D%28x-x1%29)
Absolute value is a number's distance from 0. All negatives will be converted into positives in mods
|-19| = 19
|0| = 0
|8| = 8
|-11| = 11
-19 has the highest absolute value.
First get the tangent vectors by differentiating r1 and r2

Evaluate at t=0

Use identity for angle between 2 vectors:

Evaluate dot product and unit vectors:

Sub into identity and solve for theta:

Answer:
Angle of intersection is about 79 degrees.
Please help with at least one question I’m really stressed
if she has 9, add 7. you have 16. divide it by half, 8. subtract 3 and you get 5.