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2 years ago

9

A rectangular swimming pool has a width of xyd. The length of the pool

1 answer:

Alla [95]2 years ago

4 0

Answer:

hope it helps you see the attachment for further information

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X plus 1/3 equals nine enter your answer in the box in simplest form

LekaFEV [45]

$= > x + \frac{1}{3} = 9$

$\text{Add} \: - \frac{1}{3} \: \text{ on both sides ,}$

$= > x + \frac{1}{3} - \frac{1}{3} = 9 - \frac{1}{3} \\ \\ \\ \\ = > x = \frac{(9 \times 3) - 1}{3} \\ \\ \\ \\ = > x = \frac{27 - 1}{3} \\ \\ \\ \boxed{ \bold{= > x = \frac{26}{3} }} \\ \\ \\ or , \boxed{ \bold{ \: x = 8. \bar{6}}}$

Hence,

$Value \: \: \: of \: \: x \: \: is \: \frac{26}{3} \: \: \: or \: \: \: 8. \bar{6}$

5 0

3 years ago

X=(y)/(y-3) make y the subject

Liula [17]

Answer:

$\displaystyle y=\frac{3x}{x-1}$

Step-by-step explanation:

<u>Solving Equations</u>

We have the expression:

$\displaystyle x=\frac{y}{y-3}$

And it's required to make y the subject.

It can be done by isolating y on the left side of the equation and the rest of the expression on the right side.

The first step is removing the denominator by multiplying both sides by y-3:

$\displaystyle (y-3)x=(y-3)\frac{y}{y-3}$

Simplifying the right side:

$\displaystyle (y-3)x=y$

Remove the parentheses:

$yx-3x=y$

Move the y's to the left side and the rest of the expression to the right side:

$yx-y=3x$

Factor out y:

$y(x-1)=3x$

Divide by x-1:

$\mathbf{\displaystyle y=\frac{3x}{x-1}}$

7 0

3 years ago

Suppose 100 people all toss a hat into a box and then proceed to randomly pick out a hat. what is the expected number of people

tatuchka [14]

1 person because there is 1 in 100 chance that you get your hat back

4 0

3 years ago

3. Express the mixed recurring decimal 15.732 in p/q form.

Alborosie

Answer

15717/999

Step-by-step explanation

n=15.732732

10n=157.32732

100n=1573.27327

1000n=15732.732732

n= 15.732732

999n=15717

999 999

4 0

2 years ago

Read 2 more answers

This graph represents

hram777 [196]

It is C (2, 1) I think it is because they intersect

8 0

2 years ago