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attashe74 [19]
3 years ago
7

5x+12=44 then value of 5x-12=?​

Mathematics
1 answer:
KATRIN_1 [288]3 years ago
3 0

Answer:

If 5x+12=44 then value of 5x-12 is 20

Step-by-step explanation:

5x + 12 = 44

  • The first step, we have to find the value of x

5x + 12 = 44

5x = 44 - 12

5x = 32

x = 32/5

x = 6.4

  • After that, insert the value of x into 5x - 12

5x - 12 = ...

5 ( 32/5 ) - 12

= 32 - 12

= 20

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Is a triangle with sides of length 6ft, 21 ft, 23 ft. A right triangle?
gayaneshka [121]

Answer:

No

Step-by-step explanation:

By using the Pythagoras theorem, it can be easily determined that whether the triangle is right triangle or not.

Thus, a^{2}+b^{2}=c^{2} where where a and b are the legs and c is the hypotenuse.

Let a=6ft, b=21ft and c=23ft, then

a^{2}+b^{2}=c^{2}

(6)^{2}+(21)^{2}=(23)^{2}

36+441=(23)^{2}

477=529

which is not possible, therefore the given triangle is not right triangle because it does not satisfy the Pythagoras theorem.


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3 years ago
Can you help with this?
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The slope of the given line  = 1  so the slope of the line perpendicular to it will be -(1/1)  = -1.
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y - y1 = m(x - x1)

y - -1) = -1(x - 1)
y + 1 = -x + 1
y = - x    <--------- that's the answer


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3 years ago
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ss7ja [257]

Answer:

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Step-by-step explanation:

5 0
3 years ago
I need help 9-16!!Thank u!
Trava [24]

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Step-by-step explanation:


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3 years ago
A randomized trial tested the effectiveness of diets on adults. Among 36 subjects using Diet 1, the mean weight loss after a yea
seropon [69]

Answer:

The 95%  confidence interval is

           0.45 <  \mu_1 - \mu_2  < 5.35

Step-by-step explanation:

From the question we are told that

   The first sample size is  n_1   =  36

   The first  sample mean is  \= x_1  =  3.5

   The first standard deviation is  \sigma_1  =  5.9 \ pounds

   The second  sample size is n_2 =  36

    The second  sample mean is  \= x_2 =  0.6

    The second  standard deviation is \sigma  =  4.4

Generally the degree of freedom is mathematically represented as

     df =  \frac{ [ \frac{s_1^2 }{n_1 }  + \frac{s_2^2 }{n_2} ]^2 }{ \frac{1}{(n_1 - 1 )} [ \frac{s_1^2}{n_1} ]^2 + \frac{1}{(n_2 - 1 )} [ \frac{s_2^2}{n_2} ]^2  }

=>  df =  \frac{ [ \frac{5.9^2 }{34 }  + \frac{4.4^2 }{34} ]^2 }{ \frac{1}{(34 - 1 )} [ \frac{5.9^2}{34} ]^2 + \frac{1}{(34- 1 )} [ \frac{4.4^2}{ 34} ]^2  }

=>  df =63

Generally the standard error is mathematically represented as

      SE =  \sqrt{ \frac{s_1 ^2 }{n_1}  + \frac{s_2^2 }{ n_2 } }

=>  SE =  \sqrt{ \frac{ 5.9 ^2 }{ 36 }  + \frac{ 4.4^2 }{36} }

=>  SE = 1.227

From the question we are told the confidence level is  95% , hence the level of significance is    

      \alpha = (100 - 95 ) \%

=>   \alpha = 0.05

Generally from the t distribution table the critical value  of   at a degree of freedom of is  

     t_{\frac{\alpha }{2}, 63  } =  1.998

Generally the margin of error is mathematically represented as

        E =  t_{\frac{\alpha }{2}, 63  } *  SE

=>    E =  1.998 * 1.227

=>    E =  2.45

Generally 95% confidence interval is mathematically represented as  

      (\= x_1 - \x_2) -E <  \mu

 => (3.5  - 0.6) - 2.45 <  \mu_1 - \mu_2  < (  3.5  - 0.6)  + 2.45

=>   0.45 <  \mu_1 - \mu_2  < 5.35

     

8 0
3 years ago
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