Question

What is the equation of the line passing through the points (2, –1) and (5, –10) in slope-intercept form?

Answer 1

Answer:

B.) y = - 3x + 5

Step-by-step explanation:

YOUR WELCOME!! :)

Answer 2

Answer:

y = - 3x + 5

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

To calculate m use the slope formula

m = ( y₂ - y₁ ) / ( x₂ - x₁ )

with (x₁, y₁ ) = (2, - 1) and (x₂, y₂ ) = (5, - 10)

m = $\frac{-10+1}{5-2}$ = $\frac{-9}{3}$ = - 3, hence

y = - 3x + c ← is the partial equation

To find c substitute either of the 2 points into the partial equation

Using (2, - 1 ), then

- 1 = - 6 + c ⇒ c = - 1 + 6 = 5

y = - 3x + 5 ← equation in slope- intercept form