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Y_Kistochka [10]
2 years ago
6

I really need help pls helppp meee

Mathematics
2 answers:
zhenek [66]2 years ago
8 0

Answer:

2.50t + 350 = 3t + 225

Step-by-step explanation:

Let t represent the number of tickets that each class needs to sell so that the total amount raised is the same for both classes.

One class is selling tickets for $2.50 each and has already raised $350. This means that the total amount that would be raised from selling t tickets is

2.5t + 350

The other class is selling tickets for $3.00 each and has already raised $225. This means that the total amount that would be raised from selling t tickets is

3t + 225

Therefore, for the total costs to be the same, the number of tickets would be

2.5t + 350 = 3t + 225

rodikova [14]2 years ago
6 0

Answer:

Here is the solution...hope it helps:)

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3 years ago
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According to an​ almanac, 60​% of adult smokers started smoking before turning 18 years old. ​(a) compute the mean and standard
larisa [96]
The given problem describes a binomial distribution with p = 60% = 0.6. Given that there are 400 trials, i.e. n = 400.

a.) The mean is given by:

\mu=np=400\times0.6=240

The standard deviation is given by:

\sigma=\sqrt{npq} \\  \\ =\sqrt{np(1-p)} \\  \\ =\sqrt{400(0.6)(0.4)} \\  \\ =\sqrt{96}=9.80


b.)  The mean means that in an experiment of 400 adult smokers, we expect on the average to get about 240 smokers who started smoking before turning 18 years.


c.) It would be unusual to observe <span>340 smokers who started smoking before turning 18 years old in a random sample of 400 adult​ smokers because 340 is far greater than the mean of the distribution.
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5 0
3 years ago
A school debate team has four girls and six boys. A total of four of the team members will be chosen to participate in the distr
alex41 [277]
Procedure:

1) calculate the number of diferent teams of four members that can be formed (with the ten persons)
2) calculate the number of teams tha meet the specification (two girls and two boys)
3) Divide the positive events by the total number of events: this is the result of 2) by the result in 1)

Solution

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10*9*8*7 / (4*3*2*1) = 210

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Ways of chosing 2 girls = 4*3/2 = 6

Number of different teams with 2 boys and 2 girls = 15 * 6 = 90

3) probability of choosing one of the 90 teams formed by 2 boys and 2 girls:

90/210 = 3/7
 
7 0
3 years ago
B = 73°, b = 15, c = 8 solve the triangle
malfutka [58]
Add 73 + 15 + 8 then subtract it from 190 :) hope I helped
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11111nata11111 [884]

Answer:

6 and 11

Step-by-step explanation:

n1 = n + 5

ns^2 = 3 + 3nb

6^2 = 3 + 3(11)

36 = 3 + 33

11 = 6 + 5

3 0
2 years ago
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