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3 years ago

What is 1+1???????????????????????????????????????????????

Mathematics

2 answers:

mixas84 [53]3 years ago

3 0

Answer: wow, that's a hard one, well the answer is 2

Step-by-step explanation: logic

Serggg [28]3 years ago

3 0

Answer:

Step-by-step explanation:

Hope it helps you with whatever

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A magazine reports that women trust recommendations from a particular social networking site more than recommendations from any

Misha Larkins [42]

Answer:

a) $p_A$ represent the real population proportion for women

$\hat p_A =\frac{123}{150}=0.82$ represent the estimated proportion for women

$n_A=150$ is the sample size selected for women

b) $p_B$ represent the real population proportion for male

$\hat p_B =\frac{102}{170}=0.6$ represent the estimated proportion for male

$n_B=170$ is the sample size selected for male

c) $(0.82-0.6) - 1.96 \sqrt{\frac{0.82(1-0.82)}{150} +\frac{0.6(1-0.6)}{170}}=0.124$

$(0.82-0.6) + 1.96 \sqrt{\frac{0.82(1-0.82)}{150} +\frac{0.6(1-0.6)}{170}}=0.316$

And the 95% confidence interval would be given (0.124;0.316).

We are confident at 95% that the difference between the two proportions is between $0.124 \leq p_A -p_B \leq 0.316$

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Part a

$p_A$ represent the real population proportion for women

$\hat p_A =\frac{123}{150}=0.82$ represent the estimated proportion for women

$n_A=150$ is the sample size selected for women

Part b

$p_B$ represent the real population proportion for male

$\hat p_B =\frac{102}{170}=0.6$ represent the estimated proportion for male

$n_B=170$ is the sample size elected for male

$z$ represent the critical value for the margin of error

Part c

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

The confidence interval for the difference of two proportions would be given by this formula

$(\hat p_A -\hat p_B) \pm z_{\alpha/2} \sqrt{\frac{\hat p_A(1-\hat p_A)}{n_A} +\frac{\hat p_B (1-\hat p_B)}{n_B}}$

For the 95% confidence interval the value of $\alpha=1-0.95=0.05$ and $\alpha/2=0.025$ , with that value we can find the quantile required for the interval in the normal standard distribution.

$z_{\alpha/2}=1.96$

And replacing into the confidence interval formula we got:

$(0.82-0.6) - 1.96 \sqrt{\frac{0.82(1-0.82)}{150} +\frac{0.6(1-0.6)}{170}}=0.124$

$(0.82-0.6) + 1.96 \sqrt{\frac{0.82(1-0.82)}{150} +\frac{0.6(1-0.6)}{170}}=0.316$

And the 95% confidence interval would be given (0.124;0.316).

We are confident at 95% that the difference between the two proportions is between $0.124 \leq p_A -p_B \leq 0.316$

8 0

3 years ago

What is 5/9 times 2 4/5 mixed number

Lunna [17]

5/9 * 2*5+4/5
5/9 * 10 + 4/5
5/9 * 14/5
5 * 14/9 * 5
70/9*5
70/45
14/9
1 5/9.

3 0

3 years ago

To evaluate the expression 25x-400, what would x need to be if the result must be at least 200?

Greeley [361]

Formula:
$25x - 400 \geqslant 200$
Add 400:
$25x \geqslant 600$
Divide by 25:
$x \geqslant 24$
x must at least be 24

7 0

4 years ago

V(v-1)-2(1-v) how to solve this

likoan [24]

Simply going to factorise this:

v(v - 1) -2(1 - v):
Note 1 - v = -(v-1)

v(v - 1) -2(1 - v)

v(v - 1) -2(-(v - 1))

v(v - 1) +2(v - 1)

(v + 2)(v - 1)

4 0

3 years ago

Pls help......

lora16 [44]

If the two equations in parenthesizes were there own equations which ones would equal 1 and 6
(x-1) or x=1
(3x-1) or x=1/3
3(x-1) or 3x-3 or x=1
Do you understand?

5 0

3 years ago

Read 2 more answers