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My name is Ann [436]
3 years ago
9

If Sin0=3/5, then cos0=? Apex

Mathematics
1 answer:
alexandr1967 [171]3 years ago
3 0

Answer:

4/5

Step-by-step explanation:

I believe you meant sin Ф = 3/5, since sin 0 = 0 (zero).

sin Ф = 3/5 = (opposite side) / (hypotenuse).

cos Ф          = (adjacent side) / (hypotenuse)

Use the Pythagorean Theorem to find the length of the adjacent side:

(adj)² + (opp)² = (hyp)²  becomes (adj)² = 5² - 3² = 25 - 9 = 16.

Then (adj) = +√16 = +4

and so cos Ф = (adj) / (hyp) = 4/5

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Sin = Opp./Hypo, Cos = Adj./Hypo. and Tan = Opp./Adj.

So

Sin(R) = Opp./Hypo = 60/68 = 15/17

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