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r-ruslan [8.4K]
3 years ago
8

Factor out the coefficient of the variable. The expression 38d+34 factored is

Mathematics
1 answer:
mixer [17]3 years ago
5 0
<span>the answer is 2(19d+17)</span>
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The greatest common factor of two different prime numbers is 1
Rudik [331]
I hope this helps you

5 0
3 years ago
Which expressions are equivalent to 12 - 14/3m + 2/3m ?
yawa3891 [41]
ANSWER

The correct answers are option B and D.

12 - 4m

EXPLANATION

The given expression is

12 - \frac{14}{3} m + \frac{2}{3}m

We need to simplify the above expression in order to determine the option that is equivalent to it.

The least common denominator for the last two fractions is 3.

This implies that,

= 12 + \frac{ - 14m + 2m}{3}
We simplify to obtain,

= 12 + \frac{ - 12m}{3}

This further simplifies to give us,

12 - 4m

This is option B.


When we further factor -4, we get,


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This is option D.


6 0
3 years ago
Plato algebra 2 piecewise functions
erastovalidia [21]

Answer:

Step-by-step explanation:

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6 0
3 years ago
If cos θ =-2/5 and tan θ &gt; 0, what is the value of sin θ?
dezoksy [38]
If the value of cos(θ) is negative, this angle (θ) can only be in one of two quadrants; the sine quadrant or the tan quadrant. In the sine quadrant, tan(θ) must be negative, but since tan(θ) > 0, we can safely say that the angle (<span>θ) is based in the tan quadrant.

We know that cos(</span><span>θ) = - Adjacent / Hypotenuse, and in this case Adjacent = 2 and Hypotenuse = 5. Using Pythagoras' theorem, we can find the opposite side of the right angled triangle situated in the tan quadrant...

</span>Adjacent² + Opposite² = Hypotenuse²

Therefore:

2² + Opposite² = 5²

Opposite² = 5² - 2²

Opposite² = 21

Opposite = √(21)

------------

Now, sin(θ) must be negative, as the right angled triangle is in the tan quadrant. We also know that sin(<span>θ) = Opposite / Hypotenuse, therefore:

sin(</span><span>θ) = - [</span>√(21)]/[5]
8 0
3 years ago
I need help with my homework ​
Nimfa-mama [501]
The shaded squares are positive because a negative number multiplied or divided by a negative number makes the product or quotient positive. There is no specific rule that comes to mind, but if your teacher has provided a list of specific rules I would look for something mentioning negative numbers.
6 0
3 years ago
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