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3 years ago

To calculate the area of a circle, you may use a formula. True False

Mathematics

2 answers:

Ivan3 years ago

8 0

Answer:

True.

Step-by-step explanation:

To calculate the area of a circle you have to use the formula Area = PI times radius squared.

Whitepunk [10]3 years ago

5 0

Answer:

True

Step-by-step explanation:

The formula for an area of a circle is a = pi times radius squared

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¿Cuál de las siguientes funciones es una función constante? Seleccione una: a. Y=x+1 b. Y=x+2 c. X=y+3 d. Y=3

JulijaS [17]

Answer:

Option D y=3

Step-by-step explanation:

The question in English is

Which of the following functions is a constant function?

we know that

A constant function is a function whose output value is the same for every input value

Verify each case

case A) y=x+1

This is not a constant function, this is a linear equation

Is a function whose output value is different for every input value

case B) y=x+2

This is not a constant function, this is a linear equation

Is a function whose output value is different for every input value

case C) x=y+3

This is not a constant function, this is a linear equation

Is a function whose output value is different for every input value

case D) y=3

This is a constant function

Is a function whose output value is the same for every input value

3 0

3 years ago

Wha is 3/8×5/6 you will need a paper.

icang [17]

3/8 x 5/6 = 15/48 = 5/16

4 0

2 years ago

Read 2 more answers

Two ballpoint pens are selected at random from a box that contains 3 blue pens, 2 red pens, and 3 green pens. If X is the number

Flauer [41]

Answer:

a) f(x,y) = $\frac{\binom{3}{x}\binom{2}{y}\binom{3}{2-x-y}}{\binom{8}{2}}$ ; x = 0, 1 , 2; y = 0, 1 , 2; 0 ≤ x+y ≥ 2

b) = $\frac{9}{14}$

Step-by-step explanation:

joint probability is a function that characterizes the distribution of a random variable. If X and Y be two random variables then the joint probability will be P(X = x, Y=y)

Given Data,

X = The number of blue Pens

Y = The number of red Pens

possible outcomes(X, Y) are (0, 0), (0, 1), (1, 0), (1, 1), (0, 2), (2,0)

Please refer fig. also

total number ways of selecting any 2 pens = $\binom{8}{2}$ = $\frac{8!}{2! 6!}$ =28

f(x,y) = $\frac{\binom{3}{x}\binom{2}{y}\binom{3}{2-x-y}}{\binom{8}{2}}$ ; x = 0, 1 , 2; y = 0, 1 , 2; 0 ≤ x+y ≥ 2

P(X,Y)∈A = P(X + Y ≤ 1)

= P(0,0) + P(1,0) + P(0,1)

= $\frac{3}{28}$ + $\frac{3}{14}$ + $\frac{9}{28}$

= $\frac{9}{14}$

4 0

3 years ago

guys need help asap plz ill give brainliest to first person that is correct. you put the answer for 1c and 2 below. I just need

schepotkina [342]

But where is the question???

6 0

3 years ago

Read 2 more answers

The probability that you roll a 3 on a six-sided die is . The probability that you flip a coin that lands on tails is . The prob

aivan3 [116]

Answer:

1/6; 1/2; 1/12; P(T|3) = 1/2; therefore, events are independent because P(T|3) = P(T).

Step-by-step explanation:

The probability of rolling a 3 on a six-sided die is 1/6. This is because there is one 3 out of 6 possibilities.

The probability of flipping a coin on tails is 1/2. This is because there is one side "tails" out of 2 possibilities.

The probability of rolling a 3 and flipping tails is 1/6(1/2) = 1/12.

P(T|3) = P(3 and Tails)/P(3) = 1/12 / (1/6) = 1/12(6/1) = 6/12 = 1/2

Since P(T|3) = P(3), these are independent events.

3 0

3 years ago