Find the center, vertices, and foci of the ellipse with equation 2x2 + 9y2 = 18.
1 answer:
To solve this problem you must apply the proccedure showb below:
1. You have the following equation:
<span> 2x^2+9y^2=18
2. Dividing the equation by 18, you have:
(x^2/9)+(y^2/2)=1
3. The center is:
[</span>(x-0)^2/9]3^2[(y-0)^2/√2]=1
<span>
(h,k)=(0,0)
The center is (0,0)
4. The vertices are:
a^2=9
a=3
Vertices: (-3,0) and (3,0)
5. The foci is:
c^2=a^2-b^2
c=</span>√7
<span>
The foci is: (-</span>√7,0) and (√7,0)
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