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yan [13]
3 years ago
11

Find the center, vertices, and foci of the ellipse with equation 2x2 + 9y2 = 18.

Mathematics
1 answer:
vova2212 [387]3 years ago
5 0
To solve this problem you must apply the proccedure showb below:

 1. You have the following equation:

 <span> 2x^2+9y^2=18

 2. Dividing the equation by 18, you have:

 (x^2/9)+(y^2/2)=1

 3. The center is:

 [</span>(x-0)^2/9]3^2[(y-0)^2/√2]=1
<span>
 (h,k)=(0,0)

 The center is (0,0)

 4. The vertices are:

 a^2=9
 a=3

 Vertices: (-3,0) and (3,0)

 5. The foci is:

 c^2=a^2-b^2
 c=</span>√7
<span>
 The foci is: (-</span>√7,0) and (√7,0)
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Step-by-step explanation:

The y-intercept of a line is the y value when x = 0. In the equation y = \frac23 x -3 \\, we can solve for its equation when we plug in x = 0.

Solving for y when x = 0:

y = \frac23 x -3 \\ y = \frac23 (0) -3 \\ y = -3.

So the y-intercept of the equation y = \frac23 x -3 \\ is -3.

To find what equation has the same y-intercept, we can do the same process for each equations given by the choices. However, I can see that the equation, 6x -7y = 21, has the y-intercept. If in doubt, you can check for the solution below or solve each equations for yourself.

Solving for y when x = 0:

6x -7y = 21 \\ 6(0) -7y = 21 \\ 0 -7y = 21 \\ -7y = 21 \\ \frac{-7y}{-7} = \frac{21}{-7} \\ y = -3

8 0
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DaniilM [7]

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Simplify 5 square root of 11 end root minus 12 square root of 11 end root minus 2 square root of 11 . (1 point)
Luden [163]
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Answer:

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Step-by-step explanation:

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The number of roots is determined by the degree of the polynomial.  They may be real or complex.

Since this is a 6th degree polynomial, it will have 6 roots

f(x)=3x^6+2x^5+x4-2x^3


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