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Daniel [21]
3 years ago
15

Determine the relationship between the point (1, –5) and the given system of inequalities. y ≤ 3x + 2 y > –2x – 3 Explain you

r answer both algebraically and graphically.

Mathematics
2 answers:
garik1379 [7]3 years ago
7 0

Answer: Algebraically, the point (1,-5) satisfies the first inequality, but does not satisfy the second inequality because -5 is not greater then -5.Graphically, the point (1,-5) lies in the shaded area of the first inequality but lies on the dashed line of the second inequality, which is not inclusive. Therefore, (1,5) is not a solution to the given system of inequalities.

Step-by-step explanation:

GOT IT RIGHT ON EDGE

Whitepunk [10]3 years ago
4 0

Answer:

The point is not a solution for both inequalities, so the point is not a solution for the system of inequalities.

Step-by-step explanation:

To find the relationship of the point and the system of inequalities, let's use the value of the point (x and y values) in the inequalities:

First inequality: y ≤ 3x + 2

Using x = 1 and y = -5, we have:

-5 ≤ 3*1 + 2

-5 ≤ 3 + 2

-5 ≤ 5 (True)

Second inequality: y > –2x – 3

Using x = 1 and y = -5, we have:

-5 > -2*1 - 3

-5 > -2 - 3

-5 > -5 (False)

The point is not a solution for both inequalities, so the point is not a solution for the system.

Graphically, the point is not inside the area generated by the system of inequalities (check the image attached).

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A random sample of cats at the SPCA shows that 25 out of the 40 cats are kittens. There are a total of 800 cats at all the anima
Alinara [238K]

Answer: The number of kittens= 500.

Step-by-step explanation:

Given, A random sample of cats at the SPCA shows that 25 out of the 40 cats are kittens.

i.e. ratio of kitten to cats =\dfrac{25}{40}=\dfrac{5}{8}

We assume that , the ratio will remains same.

Let x be the number of kitten out of 800 , then we have

\dfrac{x}{800}=\dfrac{5}{8}\\\\\Rightarrow\ x=\dfrac{800\times5}{8}=500

Hence, the number of kittens out of 800 cats= 500.

7 0
3 years ago
Write an equation in point slope form for the line through the given point with the given slope (5,-6) m= -0.38
tester [92]
Heeelllllloooooo! :D

Okay this is a very similar question to the one I answered earlier....

I'll show you step by step so you will be able to do this in the future on your own

(y - y₁) = m(x - x₁)     -----> point-slope form
(y + 6) = (-0.38)(x - 5)
y + 6 = -0.38x + 1.9
<u>y = -0.38x - 4.1</u><u />

There you go!

<u>Please vote me for Brainliest if there is a second answer!!!</u> ^__^
4 0
3 years ago
Select the statements that are true based on the following given information. D = {x | x is a whole number} E = {x | x is a perf
likoan [24]
<h3>2 Answers: Choice C and Choice D</h3>

==========================================================

Explanation:

Let's write the roster notation of each set

D = {0, 1, 2, 3, ...} the dots indicate the pattern goes on forever

E = {0, 1, 4, 9, 16, 25} = list of perfect squares smaller than 36

F = {20, 22, 24, 26, 28, 30} = even numbers between 20 and 30

----------------

If we intersect sets D and E, we're looking for what numbers are in both sets at the same time. Therefore, D ∩ E = {0, 1, 4, 9, 16, 25} which is the exact same as set E. This is because all of set E is inside of set D. We say that set E is a subset of set D. So, D ∩ E = E.

Choice A is very close to being true. The problem is that 25 is missing from the set {1,4,9,16}. So this is why choice A is false.

----------------

Now let's intersect sets D and F. The numbers they have in common are {20, 22, 24, 26, 28, 30} which is exactly what set F is. So set F is a subset of set D. We can write D ∩ F = F in much the same way we can say D ∩ E = E.

D ∩ F = {12,14,16,18} is not true. A number like 12 is not between 20 and 30, so it cannot be in set F.

Choice B is false so we cross it off the list.

----------------

Choice C is true and here's why

D ∪ (E ∩ F) is the same as saying D ∪ G where G is the set of intersecting E and F together. In other words, G = E ∩ F

We don't really need to even worry about sets E, F or G. All that matters here is set D.

When we write D ∪ (E ∩ F) or D ∪ G, we're saying "a number is in set D, or it is in set G". If it is in D, then it's a whole number. Otherwise, it's in a subset of whole numbers.

Overall, D ∪ G and D ∪ (E ∩ F) form the entire set of whole numbers.

------------------

Choice D is true.

E and F have nothing in common

E = {0, 1, 4, 9, 16, 25}

F = {20, 22, 24, 26, 28, 30}

So intersecting them leads to the empty set. This is the set with nothing inside it, not even 0.

------------------

Choice F is false

These two sets below

E = {0, 1, 4, 9, 16, 25}

F = {20, 22, 24, 26, 28, 30}

union together to get

H = {0,1,4,9,16,20,22,24,25,26,28,30}

just toss all of the numbers together into one big set

Notice how each of these numbers are whole numbers, so they are part of set D. This means set H is also a subset of set D.

When we intersect sets D and H, we end up with set H. We do not simply end up with the set with 25 only inside it.

6 0
3 years ago
After the 30% discount was applied, Patricia paid $45.50 for the ring. What was the original price of the ring
romanna [79]
45.50*.30 = 13.65
13.65+45.50 = 59.15 
3 0
3 years ago
Suppose that the population mean for income is $50,000, while the population standard deviation is 25,000. If we select a random
Fudgin [204]

Answer:

Probability that the sample will have a mean that is greater than $52,000 is 0.0057.

Step-by-step explanation:

We are given that the population mean for income is $50,000, while the population standard deviation is 25,000.

We select a random sample of 1,000 people.

<em>Let </em>\bar X<em> = sample mean</em>

The z-score probability distribution for sample mean is given by;

               Z = \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }  ~ N(0,1)

where, \mu = population mean = $50,000

            \sigma = population standard deviation = $25,000

            n = sample of people = 1,000

The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.

So, probability that the sample will have a mean that is greater than $52,000 is given by = P(\bar X > $52,000)

  P(\bar X > $52,000) = P( \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } } > \frac{52,000-50,000}{\frac{25,000}{\sqrt{1,000} } } ) = P(Z > 2.53) = 1 - P(Z \leq 2.53)

                                                                    = 1 - 0.9943 = 0.0057

<em>Now, in the z table the P(Z </em>\leq<em> x) or P(Z < x) is given. So, the above probability is calculated by looking at the value of x = 2.53 in the z table which has an area of 0.9943.</em>

Therefore, probability that the sample will have a mean that is greater than $52,000 is 0.0057.

5 0
3 years ago
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