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melamori03 [73]
3 years ago
10

Find the product -1/2y(2y^3-8)

Mathematics
1 answer:
Nataly_w [17]3 years ago
8 0
-2/2y^4+8/2 =(-2/2y^4)+8/2 -y^4+4.
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To convert a distance of 2790 feet to miles, which ratio could you multiply by? Remember that 1 mile = 5280 feet.
wolverine [178]
Means 1/2.......................
5 0
3 years ago
Enter the values of x, y, and z. The diagram is not to scale.
nydimaria [60]

Answer:

x = 86

y = 67

z = 94

Step-by-step explanation:

The sum of interior angles in a triangle is equal to 180

38 + 56 + x = 180

94 + x = 180 subtract 94 from both sides

x = 86

The sum of two interior angles in a triangle is equal to an exterior angle that is supplementary to the third interior angle so the value of z:

56 + 38 = 94

again the sum of interior angles in a triangle is equal to 180:

19 + z + y = 180 we found z as 94

19 + 94 + y = 180

113 + y = 180 subtract 113 from both sides

y = 67

8 0
3 years ago
What is does p equal if 8-p = -12 -3p
adelina 88 [10]

Answer:

8-p=-12-3p

8+12-p = -3p

20 = -3p + p

20 = -2p

20/-2 = p

-10 = p

ans. p = -10

...

8 0
3 years ago
Read 2 more answers
-1/4n - n= -5/6<br><br> What does n equal, Please I need this done very quickly!!
amid [387]

Answer:

n = 2/3

Step-by-step explanation:

6 0
3 years ago
What is the result of substituting for y in the bottom equation<br> y=x+3<br> y=x^2+2x-4
8_murik_8 [283]

The solutions are (2.1925, 5.1925) and (-3.1925, -0.1925)

<em><u>Solution:</u></em>

Given that,

y = x + 3 ------- eqn 1\\\\y = x^2 + 2x - 4  ----- eqn 2

<em><u>We have to substitute eqn 1 in eqn 2</u></em>

x + 3 = x^2 + 2x - 4

\mathrm{Switch\:sides}\\\\x^2+2x-4=x+3\\\\\mathrm{Subtract\:}3\mathrm{\:from\:both\:sides}\\\\x^2+2x-4-3=x+3-3\\\\\mathrm{Simplify}\\\\x^2+2x-7=x\\\\\mathrm{Subtract\:}x\mathrm{\:from\:both\:sides}\\\\x^2+2x-7-x=x-x\\\\\mathrm{Simplify}\\\\x^2+x-7=0

\mathrm{Solve\:with\:the\:quadratic\:formula}\\\\\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}\\\\x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}\\\\\mathrm{For\:}\quad a=1,\:b=1,\:c=-7\\\\x =\frac{-1\pm \sqrt{1^2-4\cdot \:1\left(-7\right)}}{2\cdot \:1}

x = \frac{-1 \pm \sqrt{ 1 + 28}}{2}\\\\x = \frac{ -1 \pm \sqrt{29}}{2}

x = \frac{ -1 \pm 5.385 }{2}\\\\We\ have\ two\ solutions\\\\x = \frac{ -1 + 5.385 }{2}\\\\x = 2.1925

Also\\\\x = \frac{ -1 - 5.385 }{2}\\\\x = -3.1925

Substitute x = 2.1925 in eqn 1

y = 2.1925 + 3

y = 5.1925

Substitute x = -3.1925 in eqn 1

y = -3.1925 + 3

y = -0.1925

Thus the solutions are (2.1925, 5.1925) and (-3.1925, -0.1925)

6 0
3 years ago
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