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Dahasolnce [82]
3 years ago
9

Mick departs Sydney on Tuesday at 6:00 am and arrives in Christchurch on Tuesday at 12:45 pm. If Christchurch time is 2 hours ah

ead of Sydney time, how long was the flight?
Mathematics
1 answer:
Andrej [43]3 years ago
7 0

Answer:

4 hours and 45 minutes.

Step-by-step explanation:

Since Christchurch is 2 hours ahead of Sydney, you subtract 2 from 12:45 and get 10:45 so then, you determine the difference between 10:45 and 6:00 AM and it results in 4.75 hours or 4 hours and 45 minutes

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Since the cable is at its lowest height 10 feet halfway between the two supports, the y-coordinate of its lowest point is -10 ft and the x coordinate is 72 ft/2 = 36 ft.

So, its vertex is at (36, -10)

Axis of symmetry

The y-axis.

Since the cable is symmetric about its lowest point, the axis of symmetry is the y-axis.

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The domain is (0, 72).

Since the minimum value of its x-coordinate is at the origin which is x = 0 and the maximum value is at the other support which is at x = 72 ft,

the domain is (0, 72).

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x and y-intercepts

The x-intercept is (0, 72) and the y-intercept is (0, 0)

Since the cable is attached at the origin and at 72 feet away  from the origin at the other support, the x-intercept is 0 and 72 ft and the y-intercepts are 0 and 0.

So, the x-intercept is (0, 72) and the y-intercept is (0, 0)

Learn more about quadratic functions here:

brainly.com/question/10606041

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<em>T</em> (<em>v</em>) = (2*0 - 3*1, 0 + 4, 5*1) = (-3, 4, 5)

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<em>T</em> (<em>u</em> + <em>v</em>) = <em>T</em> (1, 1) = (2*1 - 3*1, 1 + 4, 5*1) = (-1, 5, 5)

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Answer:

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Step-by-step explanation:

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