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Dahasolnce [82]
3 years ago
9

Mick departs Sydney on Tuesday at 6:00 am and arrives in Christchurch on Tuesday at 12:45 pm. If Christchurch time is 2 hours ah

ead of Sydney time, how long was the flight?
Mathematics
1 answer:
Andrej [43]3 years ago
7 0

Answer:

4 hours and 45 minutes.

Step-by-step explanation:

Since Christchurch is 2 hours ahead of Sydney, you subtract 2 from 12:45 and get 10:45 so then, you determine the difference between 10:45 and 6:00 AM and it results in 4.75 hours or 4 hours and 45 minutes

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1.4 x 10⁵ 

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hank is working in a silver mine 10ft below the surface. he descends until he reaches a point 57ft below the surface. how many f
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3 0
3 years ago
UJUU J
Stels [109]

Answer:

Plese read the complete procedure below:

Step-by-step explanation:

The polynomial is p(a) = (a^4 - 6a^3 + 3a^2 + 26a – 24)

a)

1   -6   3   26   -24    |<u>  1     </u>

<u>      1   -5   -2    24</u>

1   -5   -2   24    0

The remainder is zero, then (a-1) is a factor of the polynomial

b)

1   -6   3   26   -24    |<u>  2     </u>

<u>      2  -8   10    72</u>

1   -4   5   36    48

When p(a) is divided by (a-2) the remainder 28/p(a)

1   -6   3   26   -24    |<u> - 4     </u>

<u>    -4  40  172  -792</u>

1   -10  43  198  -816

When p(a) is divided by (a-2) the remainder -816/p(a)

c) I attached an image of the long division below:

3 0
3 years ago
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