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vovikov84 [41]
3 years ago
8

Which of the following best defines the two quantities that are measured to find the call rate of a phone company? The quantity

of price measured in dollars depends on the quantity of time measured in minutes. The quantity of time measured in minutes depends on the quantity of price measured in dollars. The quantity of time measured in minutes depends on the quantity of speed measured in calls per minute. The quantity of speed measured in calls per minute depends on the quantity of time measured in minutes.
Mathematics
2 answers:
schepotkina [342]3 years ago
7 0
"The quantity of price measured in dollars depends on the quantity of time measured in minutes" is an example that best defines the two quantities that are measured to find the call rate of a cell phone company.
pochemuha3 years ago
6 0

Answer:

A. the quantity of price measured in dollars depends on the quantity of time measured in minutes.

Step-by-step explanation:

The following best defines the two quantities that are measured to find the call rate of a phone company:

A. the quantity of price measured in dollars depends on the quantity of time measured in minutes.

In this way we can determine that how much money will it cost in dollars for each minute of phone call.

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Solve the equation, if possible.
Shalnov [3]

Answer:

no solution

Step-by-step explanation:

Given

- 3 | 6n - 2 | + 5 = 8 ( subtract 5 from both sides )

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| 6n - 2 | = - 1

The absolute value always returns a positive value and so

| 6n - 2 | ≠ - 1

Hence there is no solution to the equation

4 0
3 years ago
What estimate can you make for 1/2 and 4/6?
densk [106]
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5 0
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GarryVolchara [31]
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What is the answer to <br>|5 + -4|
luda_lava [24]

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3 0
3 years ago
Write an equation that represents the line. (-3,-6) and (2,-2) use exact numbers
Ilia_Sergeevich [38]

Given:

The line passes through (-3,-6) and (2,-2).

To find:

The equation of line.

Solution:

If a line passes through two points (x_1,y_1)\text{ and }(x_2,y_2), then the equation of line is

y-y_1=\dfrac{y_2-y_1}{x_2-x_1}(x-x_1)

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y-(-6)=\dfrac{-2-(-6)}{2-(-3)}(x-(-3))

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y+6=\dfrac{4}{5}(x+3)

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Subtract 6 from both sides.

y=\dfrac{4}{5}(x)+\dfrac{12}{5}-6

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3 0
3 years ago
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