Answer:
(15,-14)
Step-by-step explanation:
Given that,
The midpoint of FG is (6-4) and the corrdinates of F are (-3,6).
Let (x,y) be the coordinates of point G. Using mid point formula,

So, the coordinates of G are (15,-14).

Break the expression into group:

factor out x from 4x² - 5x : x (4x-5)
factor out 3 from 12x-15 : 3 (4x-5)

factor out common term (4x-5) :

hope this helps!
Answer:
f(x) = -3(x - 5)^2 + 4
vertex (5,4)
Step-by-step explanation:
f(x) = -3x² +30x - 71
f(x) = -3(x² +-10x) - 71
f(x) = -3(x² +-10x+5^2-5^2) - 71
f(x) = -3(x² +-10x+5^2) -3(-5^2) - 71
f(x) = -3(x² +-10x+5^2) + 4
f(x) = -3(x - 5)^2 + 4
vertex (5,4)
Answer:
The answer is "
"
Step-by-step explanation:
In point a:
The requires 1 genin, 1 chunin , and 1 jonin to shape a complete team but we all recognize that each nation's team is comprised of 1 genin, 1 chunin, and 1 jonin.
They can now pick 1 genin from a certain matter of national with the value:

They can pick 1 Chunin form of the matter of national with the value:

They have the option to pick 1 join from of the country team with such a probability: 
And we can make the country teams:
different forms. Its chances of choosing a team full in the process described also are:
In point b:
In this scenario, one of the 3 professional sides can either choose 3 genins or 3 chunines or 3 joniners. So, that we can form three groups that contain the same ninjas (either 3 genin or 3 chunin or 3 jonin).
Its likelihood that even a specific nation team ninja would be chosen is now: 
Its odds of choosing the same rank ninja in such a different country team are: 
The likelihood of choosing the same level Ninja from the residual matter of national is:
Therefore, all 3 selected ninjas are likely the same grade: 
The answer is D. - 17 because 17 - 17 = 0
Have a nice day!