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Svetlanka [38]
3 years ago
15

How do you solve (3x)^-2

Mathematics
1 answer:
zmey [24]3 years ago
6 0

Answer:

\frac{1}{9x^{2} }

Step-by-step explanation:

(3x)^{-2}

Distribute exponent

3^{-2} x^{-2}

put negatives on the bottom

\frac{1}{3^{2}  x^{2} }

SImplify

\frac{1}{9x^{2} }

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