3 years ago

How do you solve (3x)^-2

Mathematics

1 answer:

zmey [24]3 years ago

6 0

Answer:

$\frac{1}{9x^{2} }$

Step-by-step explanation:

$(3x)^{-2}$

Distribute exponent

$3^{-2} x^{-2}$

put negatives on the bottom

$\frac{1}{3^{2} x^{2} }$

SImplify

$\frac{1}{9x^{2} }$

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Step-by-step explanation:

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