Domain is the x-values
Range is the y-values
To identify the range, plug in the x-values they gave you into the equation to find its y-value
x = 3
y = 2x + 4 Plug in 3 for x
y = 2(3) + 4
y = 10
x = 5
y = 2x + 4 Plug in 5 for x
y = 2(5) + 4
y = 10 + 4
y = 14
x = 6
y = 2x + 4 Plug in 6 for x
y = 2(6) + 4
y = 16
x = 8
y = 2x + 4 Plug in 8 for x
y = 2(8) + 4
y = 20
The range is {10, 14, 16, 20}
Answer:
The roots are not real.
Step-by-step explanation:
To prove : The roots of I/2 +9 (1-k) are real for all real values of k ?Solution :
The roots are real when discriminant is greater than equal to zero.
i.e b2-4ac>0 But the roots are imaginary therefore the roots of the given equation are not real for any value of k.If x²+kx+k=0, find the value of k, If the roots are real & equal.
Answer:
Option (4)
Step-by-step explanation:
Given system of equations is,
y = -x²- 4x - 3
y = 2x + 5
To get the solution of the system of equations algebraically,
2x + 5 = -x²- 4x - 3
Now combine like terms onto one side of the equation.
-x² - (4x + 2x) - (3 + 5) = 0
x² + 6x + 8 = 0
Then factorize the equation,
x² + 4x + 2x + 8 = 0
x(x + 4) + 2(x + 4) =0
(x + 2) (x + 4) = 0
x = -2, 4
Option (4) is the answer.