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3 years ago

5

I need help, it is urgent

1 answer:

quester [9]3 years ago

5 0

Well for answer 23 is -6 √(5) + 6 √(2).
The answer for 25 is -3 √(5) - 2 √(6)
And the answer for 27 is -15 √(5) + 4 √(3) + 3 √(6)

Hope this helps :)

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I need the answer for this please

Jlenok [28]

Since T is the midpoint of PQ, this means that PT and TQ must be equal to each other. Make them equal to each other in an equation.

PT = TQ

4x + 2 = 7x - 7

Subtract 2 from both sides.

4x = 7x - 9

Subtract 7x from both sides.

-3x = -9

Divide both sides by -3.

<u>x = 3</u>

Now substitute 3 for x into PT.

PT = 4(3) + 2

PT = 12 + 2

<h3>PT = 14</h3>

5 0

3 years ago

Factor f(x)=x4-x3-7x2+13x-6 completely. Then Sketch the graph

Dennis_Churaev [7]

ANSWER TO QUESTION 1

$f(x)=(x-2)(x+3)(x-1)^2$ .

EXPLANATION

The function given to us is,

$f(x)=x^4-x^3-7x^2+13x-6$

According to rational roots theorem,

$\pm1,\pm2,\pm3,\pm6$ are possible rational zeros of

$f(x)=x^4-x^3-7x^2+13x-6$ .

We find out that,

$f(-3)=(-3)^4-(-3)^3-7(-3)^2+13(-3)-6$

$f(-3)=81+27-63-39-6$

$f(-3)=6-6$

$f(-3)=0$

Also

$f(2)=(2)^4-(2)^3-7(2)^2+13(2)-6$

$f(2)=16-8-28+26-6$

$f(2)=6-6$

$f(2)=0$

This implies that

$x-2 and x+3$ are factors of

$f(x)=x^4-x^3-7x^2+13x-6$ and hence $(x-2)(x+3)=x^2+x-6$ is also a factor.

We perform the long division as shown in the diagram.

Hence,

$f(x)=(x-2)(x+3)(x-1)^2$ .

ANSWER TO QUESTION 2

Sketching the graph

We can see from the factorization that the roots

$x=2$ and $x=-3$ have a multiplicity of 1, which is odd. This means that the graph crosses the x-axis at this intercepts.

Also the root $x=1$ has a multiplicity of 2, which is even. This means the graph does not cross the x-axis at this intercept.

Now we determine the position of the graph on the following intervals,

$x\le -3$

$f(-4)=(-4)^4-(-4)^3-7(-4)^2+13(-4)-6$

$f(-4)=150\:>0$

$-3\le x \le 1$

$f(0)=-6\:$

$1\le x\le 2$

$f(1.5)=-0.56\:$

$x \ge 2$

$f(3)=24\:>0$

We can now use these information to sketch the function as shown in diagram

4 0

3 years ago

Carly is a catcher on the school softball team. By the end of the season, she had played 45% of the 49 games the team played. In

Eduardwww [97]

Carly did not play 22 games

6 0

3 years ago

Find f(-1) I really need help with this please somebody help

sattari [20]

Answer:

Graph the line using the slope and y-intercept, or two points.

Slope: −1-1

y-intercept: (0,0)(0,0)

xy−1100

Step-by-step explanation:

7 0

3 years ago

a construction company charges $15 per hour for debris removal , plus a one -time fee for the use of the trash dumpster.the tota

ser-zykov [4K]

Let h be the numbers of hours, f be the one-time fee and c the cost charged. The equation is

$c=15h+f$

Since you pay $15 per four, plus the fee. We can solve this equation for the fee:

$f=c-15h$

If we plug c=195 and h=9, we have

$f=195-15\cdot 9=195-135=60$

6 0

3 years ago