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Alex
3 years ago
5

How does the catalyst affect the magnitude of the activation energy?

Chemistry
1 answer:
Sati [7]3 years ago
5 0

Answer:

speeds up

Explanation:

catalysts decrease the activation energy required for a reaction to proceed

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Calculate the volume of one mole of a gas at 1.00 atm pressure and 0 °C.
N76 [4]

Answer:

Solution:-

The gas is in the standard temperature and pressure condition i.e. at S.T.P

Therefore,

V

i

​

=22.4dm

3

V

f

​

=?

As given that the expansion is isothermal and reversible

∴ΔU=0

Now from first law of thermodynamics,

ΔU=q+w

∵ΔU=0

∴q=–w

Given that the heat is absorbed.

∴q=1000cal

⇒w=−q=−1000cal

Now,

Work done in a reversible isothermal expansion is given by-

w=−nRTln(

V

i

​

V

f

​

​

)

Given:-

T=0℃=273K

n=1 mol

∴1000=−nRTln(

V

i

​

V

f

​

​

)

⇒1000=−1×2.303×2×273×log(

22.4

V

f

​

​

)

Explanation:

6 0
3 years ago
Hydrogen sulfide decomposes according to the following reaction: 2H2S(g) ⇋ 2H2(g) + S2(g) Kc=9.30x10-8 at 700.°C.If 0.45 mol of
Natalija [7]

Answer:

[H₂] = 1.61x10⁻³ M

Explanation:

2H₂S(g) ⇋ 2H₂(g) + S₂(g)

Kc = 9.30x10⁻⁸ = \frac{[H_{2}]^2[S_{2}]}{[H_{2}S]^2}

First we <u>calculate the initial concentration</u>:

0.45 molH₂S / 3.0L = 0.15 M

The concentrations at equilibrium would be:

[H₂S] = 0.15 - 2x

[H₂] = 2x

[S₂] = x

We <u>put the data in the Kc expression and solve for x</u>:

\frac{(2x^2) * x}{(0.15-2x)^2}=9.30x10^{-8}

\frac{4x^3}{0.0225-4x^2}=9.30*10^{-8}

We make a simplification because x<<< 0.0225:

\frac{4x^3}{0.0225} =9.30*10^{-8}

x = 8.058x10⁻⁴

[H₂] = 2*x = 1.61x10⁻³ M

5 0
3 years ago
Read 2 more answers
12 = 3X X = <br> 7X = 57 X = <br> 11X = 27.7 X =
dybincka [34]

Answer:
1. x=4
2.x=\frac{57}{7}
3.x=\frac{27.7}{11}

Explanation:

Given the following questions:

12=3x
7x=57
11x=27.7

In order to find the answers to these questions, we have to recognize that in order to isolate the variable we need to divide on both sides.

Question one:
12=3x
\frac{3x}{3} =\div3
12\div3=4
x=4

Question two:
7x=57
\frac{7x}{7} =\div7
57\div7=8.14285714=\frac{57}{7}
x=\frac{57}{7}

Question three:
11x=27.7
\frac{11x}{11} \div11
27.7\div11=2.51818182=\frac{27.7}{11}
x=\frac{27.7}{11}

Hope this helps.

3 0
2 years ago
1. Most fruit juices are a solution of water, sugar, and fruit-specific chemicals. In this solution, identify the solvent and so
lianna [129]
In this case, we can say that water is the solvent. Solvent by definition are the part of the solution that is present in the largest amount. The fruit juice are all dilute by the water. Everything else in the fruit juice can be called the solute, they are what is "dissolved" in the solvent (sugar, fruit juice, etc.).   

Hoped I helped!
5 0
4 years ago
If the smallest markings on a ruler are one tenth (1/10) of a centimeter, which of the following measurements could be recorded
makkiz [27]
I think it should be A 
4 0
4 years ago
Read 2 more answers
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