Answer:
x=±0.026m
Explanation:
In simple harmonic motion the maximum value of the magnitude of velocity
The speed as a function of position for simple harmonic oscillator is given by
where A is amplitude of motion
Given data
Amplitude A=3 cm =0.03 m
v=(1/2)Vmax
To find
We have asked to find position x does its speed equal half of is maximum speed
Solution
The speed of the particle the maximum speed as:
x=±(√3(0.03)/2)
x=±0.026m
Answer:
The work done is zero
Explanation:
No work is performed or required in moving the positive charge from point A to point B
C- Incentives it’s like a reward ~!
D. It is about 100,000 times larger.
A commonly used comparison is that of a pea in the middle of a racetrack.
Answer:
3 seconds
Explanation:
t = Time taken
u = Initial velocity
v = Final velocity
s = Displacement
a = Acceleration due to gravity = 32 ft/s²
174 feet from the ground is 174-14 = 160 ft from the launch area
When the arrow will reach the 160 ft point while returning the initial velocity becomes equal to the final velocity which means the time taken to come down also becomes equal.
Hence, the arrow will be 1.5+1.5 = 3 seconds above a height of 174 ft from the ground.