Where should i graph the distance in a distance time graph

If the velocity of a pitched ball has a magnitude of 44.5 m/sm/s and the batted ball's velocity is 55.5 m/sm/s in the opposite d

Yuliya22 [10]

Incomplete question as the mass of baseball is missing.I have assume 0.2kg mass of baseball.So complete question is:

A baseball has mass 0.2 kg.If the velocity of a pitched ball has a magnitude of 44.5 m/sm/s and the batted ball's velocity is 55.5 m/sm/s in the opposite direction, find the magnitude of the change in momentum of the ball and of the impulse applied to it by the bat.

Answer:

ΔP=20 kg.m/s

Explanation:

Given data

Mass m=0.2 kg

Initial speed Vi=-44.5m/s

Final speed Vf=55.5 m/s

Required

Change in momentum ΔP

Solution

First we take the batted balls velocity as the final velocity and its direction is the positive direction and we take the pitched balls velocity as the initial velocity and so its direction will be negative direction.So we have:

$v_{i}=-44.5m/s\\v_{f}=55.5m/s$

Now we need to find the initial momentum

So

$P_{1}=m*v_{i}$

Substitute the given values

$P_{1}=(0.2kg)(-44.5m/s)\\P_{1}=-8.9kg.m/s$

Now for final momentum

$P_{2}=mv_{f}\\P_{2}=(0.2kg)(55.5m/s)\\P_{2}=11.1kg.m/s$

So the change in momentum is given as:

ΔP=P₂-P₁

$=[(11.1kg.m/s)-(-8.9kg.m/s)]\\=20kg.m/s$

ΔP=20 kg.m/s

3 0

4 years ago

Please... what are the differences between alternators and generators

astraxan [27]

The difference between them is in regard to what spins and what is fixed. In an alternator<span>, electricity is produced when a magnetic field spins inside the stator (windings of wired) </span>

7 0

4 years ago

In Part C, how would the effects differ if you connected the galvanometer to the primary coil and the battery/switch to the seco

Katen [24]

N₂ / N₁ = 13.3

A transformer is a device that changes the voltage in the primary, causing a voltage to be induced in the secondary. The expression for this voltage ratio is

ΔV₂ = N₂ /N₁ ΔV₁

where N is the number of windings on each side and V2 and V1 are the voltages in the secondary and primary, respectively.

They state that the primary voltage in this instance is 9.0 V and the secondary voltage is 120 V.

ΔV₂ /ΔV₁ = N₂ / N₁

N₂ / N₁ = 120/9

N₂ / N₁ = 13.3

Learn more about voltage here brainly.com/question/16774947

#SPJ4.

A 9.0-V battery (with nonzero resistance) and switch are connected in series across the primary coil of a transformer. The secondary coil is connected to a light bulb that operates on 120 V. Determine the ratio of the secondary to primary turns needed for the bell's transformer. Determine the ratio of the secondary to primary turns needed for the bells transformer. Ns/Np=?

4 0

2 years ago

Why do nuclear power plants use fission rather than fusion to generate

kicyunya [14]

B. Fusion requires very high pressure and temperature.

Explanation:

Nuclear fusion is the combination of atomic nuclei into larger ones with the release of a large amount of energy.

Nuclear fission is the decay process in which a heavy nuclide is bombarded with with neutrons.

Both processes release a huge amount of energy.
But fusion produces far more energy.
The reason why nuclear fusion is not in use is because of the high pressure and temperature needed start it.
The activation energy is high and the energy barrier is very great.
Only the core of the sun naturally favors fusion

learn more:

transmutation brainly.com/question/3433940

#learnwithBrainly

5 0

3 years ago

Read 2 more answers

A 22-turn circular coil of radius 3.00 cm and resistance 1.00 Ω is placed in a magnetic field directed perpendicular to the plan

zloy xaker [14]

Answer:

23.5 mV

Explanation:

number of turn coil 'N' =22

radius 'r' =3.00 cm=> 0.03m

resistance = 1.00 Ω

B= 0.0100t + 0.0400t²

Time 't'= 4.60s

Note that Area'A' = πr²

The magnitude of induced EMF is given by,

lƩl =ΔφB/Δt = N (dB/dt)A

=N[d/dt (0.0100t + 0.0400 t²)A

=22(0.0100 + 0.0800(4.60))[π(0.03)²]

=0.0235

=23.5 mV

Thus, the induced emf in the coil at t = 4.60 s is 23.5 mV

8 0

3 years ago