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nikklg [1K]
3 years ago
7

What are 3 x-intercepts of f(x)=x^2-8x+7

Mathematics
1 answer:
Nadya [2.5K]3 years ago
7 0

Answer:

you use to computer:

x1=7

x2=1

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Write and solve an inequality to find the values of x for which the perimeter of the rectangle is less than 120.
RSB [31]

Answer:

Inequality : 4x+8 < 120

x<28

Step-by-step explanation:

Hi, to answer this question we have to apply the next formula:

Perimeter of a rectangle (P)= 2 length +2 width

Where:

Width = x

Length = x+4

Replacing with the values given

P = 2 (x+4) + 2x

P = 2x+8+2x

P=4x+8

Since the perimeter of the rectangle must be less than 120:

4x+8 < 120

Solving for x

4x<120-8

4x<112

x<112/4

x<28

Feel free to ask for more if needed or if you did not understand something.  

4 0
3 years ago
Please help with this problem <br> 2x/3−6=4
Zarrin [17]
2x/3-6=4. 2x/3=4+6. 2x/3=10. 2x=10*3. 2x=30. X=30/2. x=15.
5 0
3 years ago
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NemiM [27]
The Answer is 2/3

Steps: 1/4(1-(2/3^2+1/3)
3 0
3 years ago
HELP!
artcher [175]

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6 0
2 years ago
The sum of two numbers is
bekas [8.4K]
Okay you have 2 sum unknow lets call them X+Y

so X+Y=33, 4X=108

Get X by it self then plug it in 4X=108

X=-Y+33
4(-y+33)= 108
-4y+132=108 Then subtract the 132
-4y=-24 Y=6 then to find X subtract 33-6=27
Y=6 X=27 if you check it works out
3 0
3 years ago
Read 2 more answers
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