3 years ago

Dominque lives One in 1 and

Mathematics

1 answer:

Ludmilka [50]3 years ago

6 0

The answer to your question is 3/4

You might be interested in

Points for points?

sattari [20]

All the best!!

thanks for the points!

it was nice to meet you <3

6 0

2 years ago

Four cups of flour make 5/6 batch of bread. How many cups of flour make 1 batch?

melisa1 [442]

Answer:

1 and 1/4ths a cup to make a batch if i worded that right

5 0

1 year ago

un carpintero tiene un listón de 12metros de longitud. quiere dividirlo en trozos iguales que midan siempre un numero exacto de

san4es73 [151]

Answer:

Step-by-step explanation:

6 metros multiplicado por 2 metros o 3 metros multlipicado 4 metros

5 0

3 years ago

Read 2 more answers

Someone plsss help - find x

Leokris [45]

Answer:

96 + 150 + 2x + x = 360⁰

240 + 3x = 360⁰

3x = 120

x = 40⁰ hope it's help you

7 0

2 years ago

Read 2 more answers

Find lim x→3 sqrt 2x+3-sqrt 3x/ x^2-3x. you must show your work or explain your work in words plsss I need help

sineoko [7]

I'm assuming the limit is supposed to be

$\displaystyle\lim_{x\to3}\frac{\sqrt{2x+3}-\sqrt{3x}}{x^2-3x}$

Multiply the numerator by its conjugate, and do the same with the denominator:

$\left(\sqrt{2x+3}-\sqrt{3x}\right)\left(\sqrt{2x+3}+\sqrt{3x}\right)=\left(\sqrt{2x+3}\right)^2-\left(\sqrt{3x}\right)^2=-(x-3)$

so that in the limit, we have

$\displaystyle\lim_{x\to3}\frac{-(x-3)}{(x^2-3x)\left(\sqrt{2x+3}+\sqrt{3x}\right)}$

Factorize the first term in the denominator as

$x^2-3x=x(x-3)$

The $x-3$ terms cancel, leaving you with

$\displaystyle\lim_{x\to3}\frac{-1}{x\left(\sqrt{2x+3}+\sqrt{3x}\right)}$

and the limand is continuous at $x=3$ , so we can substitute it to find the limit has a value of -1/18.

7 0

2 years ago