H = 151t - 16t²
The height of the ball when it return to the ground will be 0
0 = 151t - 16t²
The zero product property is that when two numbers are being multiplied and the product is 0, one of them must be equal to 0. Therefore, we can factorize this equation:
16t² - 151t = 0
t(16t - 151t) = 0
By the zero product property:
t = 0 or 16t - 151 = 0
So t = 0 or t = 9.44 seconds
The first solution is before he releases the ball and the second is when the ball comes back to the ground. Thus, the ball's air time is 9.44 seconds.
Answer:
Step-by-step explanation:
Answer:
(2x² + 5x + 2) = (2x + 1)(x +2)
Step-by-step explanation:
Given expression is (2x² + 5x + 2).
We have to factorize the given expression.
(2x²+ 5x + 2) = 2x² + 4x + x + 2
= 2x(x + 2) + 1(x + 2)
= (2x + 1)(x + 2)
So the factored form of the given expression will be (2x + 1)(x + 2).
Given equation : 
.
Strategy 1: We can cross mutiply both sides remove fraction form.
On cross multiplication, we get
x * 7 = 3 * 42
7x = 126.
Dividing both sides by 7, we get
<h3>
x = 18.</h3>
Strategy 2: We can find least common denominator(lcd) of both sides and multiplying both sides by that lcd to get rid denominators from both sides.
LCD of 42 and 7 is 42.
Therefore, multiplying both sides by 42, we get
x = 6 * 3
<h3>x = 18.</h3>
