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Neko [114]
4 years ago
13

13. Calcule:

Mathematics
1 answer:
8090 [49]4 years ago
6 0
Your answer will be B.
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If f(x)=x²+2x then find f(2) and f(8)​
kobusy [5.1K]

Answer:

f(2) = 8, f(8) = 80

Step-by-step explanation:

f(x)=x(x+2)

f(2)=2(2+2)=2(4)=8\\f(8)=8(8+2)=8(10)=80

5 0
3 years ago
Melody wants to buy a shirt the shirt cost $65 and the store is offering a 25 discount what is the sale price
bixtya [17]

Answer:

48.75

Step-by-step explanation:

5 0
3 years ago
F(x) = 9-5x<br> For the function<br> 3+x<br> f-1(x).<br> find
Iteru [2.4K]

Answer:

f x − x + 3

Step-by-step explanation:

Substitute the given value into the function and evaluate.

PLEASE MARK BRAINLIEST!!

3 0
3 years ago
Please help!?
Alex787 [66]

Answer:

x=63.25

Step-by-step explanation:

Hi there!

We're given ΔDEF with m<E=90°, m<D=49°, DE=55, and EF=x

we need to find the value of x

Let's use trigonometry to do it

Since we are given the measures of the 2 legs (the sides that make up the 90° angle), let's use tangent, specifically tan(49), since we are given the measure of that angle

Recall that tangent is \frac{opposite}{adjacent}

in reference to m<D (the angle that is 49°), the opposite side is EF (x) and the adjacent side is DE (55)

so tan(49)=\frac{x}{55}

plug tan(49) into your calculator; remember to have the calculator on degree mode

tan(49)≈1.15 (rounded to the nearest hundredth)

so that means:

1.15=\frac{x}{55}

multiply both sides by 55 to clear the fraction

63.25=x

Hope this helps!

5 0
3 years ago
Given: <br> PQ<br> ⊥<br> QR<br> , PR=20,<br> SR=11, QS=5<br> Find: The value of PS.
dlinn [17]

Answer:

The value of the side PS is 26 approx.

Step-by-step explanation:

In this question we have two right triangles. Triangle PQR and Triangle PQS.

Where S is some point on the line segment QR.

Given:

PR = 20

SR = 11

QS = 5

We know that QR = QS + SR

QR = 11 + 5

QR = 16

Now triangle PQR has one unknown side PQ which in its base.

Finding PQ:

Using Pythagoras theorem for the right angled triangle PQR.

PR² = PQ² + QR²

PQ = √(PR² - QR²)

PQ = √(20²+16²)

PQ = √656

PQ = 4√41

Now for right angled triangle PQS, PS is unknown which is actually the hypotenuse of the right angled triangle.

Finding PS:

Using Pythagoras theorem, we have:

PS² = PQ² + QS²

PS² = 656 + 25

PS² = 681

PS = 26.09

PS = 26

7 0
3 years ago
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