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ddd [48]
4 years ago
10

Nancy spent 3 2/6 hours working on her homework,while her sister Sally spent 1 8/12 hours working on her homework.How many more

hours did Nancy spend on homework than Sally?
Mathematics
1 answer:
salantis [7]4 years ago
7 0

Answer:

Nancy Spent  1\frac{8}{12} hours more than Sally.

Step-by-step explanation:

Given:

Nancy spent 3 2/6 hours working on her homework.

Hours spent on Homework by Nancy = 3\frac{2}{6}

3\frac{2}{6} can be Rewritten as \frac{20}{6}

Hours spent on Homework by Nancy = \frac{20}{6}

Also Given;

Sally spent 1 8/12 hours working on her homework.

Hours spent on Homework by Sally = 1\frac{8}{12}

1\frac{8}{12} can be Rewritten as \frac{20}{12}

Hours spent on Homework by Sally = \frac{20}{12}

We need to find Hours spent more by Nancy;

It can be calculated by subtracting Hours spent by Sally with Hours spent by Nancy;

Hours Spent More = \frac{20}{6}-\frac{20}{12}

Now we will make the denominators common then solve for the same.

Hours Spent More =\frac{20\times 2}{6\times2}-\frac{20\times1}{12\times1}= \frac{40}{12}-\frac{20}{12}= \frac{40-20}{12}= \frac{20}{12} \ hrs

Hence \frac{20}{12} \ hrs can be rewritten as  1\frac{8}{12}.

Hence Nancy Spent  1\frac{8}{12} hours more than Sally.

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