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m_a_m_a [10]
3 years ago
8

(8 × 2) × 5 = 8 × (2 × 5)

Mathematics
2 answers:
Aleonysh [2.5K]3 years ago
7 0
80 = 80

hope that helps. you didn’t specify what you’re looking for.
S_A_V [24]3 years ago
4 0

Answer:

3 1/5

Step-by-step explanation:

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In the algebraic expression 7/y why is coefficient of y? Explain.
dybincka [34]

Answer:

7 is the (constant) coefficient of 1/y, but no, it is not the coefficient of y

Step-by-step explanation:

7/y can be rewritten as 7(1/y) or as 7(y^[-1]).  In this case, yes, 7 is the (constant) coefficient of 1/y, but no, it is not the coefficient of y.

3 0
3 years ago
Absolute values can be _____<br><br>&lt;one word&gt;
bulgar [2K]
Positive
Yo is this math?
6 0
3 years ago
A stack of two hundred ten cards is placed next to a ruler, and the height of the stack is measured to be 7/8 inches. How thick
Naily [24]
(7/8) divided by 200
each card is 0.004375 inches thick
3 0
3 years ago
I WILL GIVE BRAINLEST!!! (6 points!)
vlada-n [284]

Answer:

OPTION A: 2x + 3y = 5

Step-by-step explanation:

The product of slopes of two perpendicular lines is -1.

We rewrite the given equation as follows:

2y = 3x + 2

⇒ y = $ \frac{3}{2}x + 1 $

The general equation of the line is: y = mx + c, where 'm' is the slope of the line.

Here, m = $ \frac{3}{2} $.

Therefore, the slope of the line perpendicular to the line given = $ \frac{-2}{3} $ because $ \frac{3}{2} \times \frac{-2}{3} = -1 $.

To determine the equation of the line passing through the given point and a slope we use the Slope - One - point formula which is:

                                  y - y₁ = m(x - x₁)

The point is: (x₁, y₁) = (-2, 3)

Therefore, the equation is:

y - 3 = $ \frac{-2}{3} $(x + 2) $

⇒ 3y - 9 = -2(x + 2)

⇒ 3y - 9 = -2x - 4

⇒ 2x + 3y = 5 is the required equation.

6 0
3 years ago
Read 2 more answers
The side length of a square ice cube is claimed to be 1.0 inches, correct to within 0.001 inch. Use linear approximation to esti
Olenka [21]

Answer:

0.012

Step-by-step explanation:

Linear approximation says that,

f(x) \approx f(x_o)+f'(x_o)(x-x_o)

For a cube the surface area is 6x^2.

So the side is 1.0 inch in, the surface area is =6\times1^2 = 6 square inches.  

In Linear approximation means you ignore the term x_o^2 , if x_o is a small number, because then x_o^2 will be a very smalle number and that does not contribute much to the error.  

So the surface area is approximately,

6x^2=6x_o^2+12x_o(x-x_o)

So here, x=1.001, x_o=0.001

The error in the area is approximately,

12 \times 0.001=0.012

So the error is 0.012.


3 0
3 years ago
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