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2 years ago

(8 × 2) × 5 = 8 × (2 × 5)

Mathematics

2 answers:

Aleonysh [2.5K]2 years ago

7 0

80 = 80

hope that helps. you didn’t specify what you’re looking for.

S_A_V [24]2 years ago

4 0

Answer:

3 1/5

Step-by-step explanation:

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Please do correctly! I will mark you Brainliest!

kolbaska11 [484]

Answer:

3(4+√2)

Step-by-step explanation:

Here we need to find the perimeter of the given figure. Here the given figure is made from a triangle and a square. The side lenght of the square is 3. We need to find the hypontenuse of the triangle in order to find Perimeter .

• Using Pythagoras Theorem :-

⇒ h² = p² + b²

⇒ h² = 3² + 3²

⇒ h² = 9 + 9

⇒ h² = 18

⇒ h = √[ 9 × 2 ]

⇒ h = 3√2 .

Therefore the perimeter will be ,

⇒ P = 3√2 + 3 + 3 + 3 + 3

⇒ P = 3√2 + 12

⇒ P = 3( 4 + √2)

<h3>Hence the perimeter of the figure is 3(4+√2) .</h3>

4 0

3 years ago

Can anybody tell me what is the answer to -2/5 - (-1/10)

liubo4ka [24]

$\frac{ - 3}{10}$

Hope it helps

6 0

1 year ago

At a bake sale, Tia and Jaden earned $147 from the cookies they had sold. Then they paid Tia’s mother back $18 for materials to

nadya68 [22]

Answer: The total profit is $129

Step-by-step explanation:

The total revenue, was $147 (the total they earned), and the cost of the materials is $18 (how much they returned for the materials)

The total profit is computed as the difference between the revenue and the costs, then the total profit of the kids in this case is:

Profit = $147 - $18 = $129

This means that Tia and Jaden earned $129, if they divide it evenly, each one of them gets $129/2 = $64.5

3 0

2 years ago

A school baseball team earned $3416.90 from selling 5716 tickets to their game. If grandstand tickets sold for 65 cents each and

expeople1 [14]

If all were grandstand tickets, revenue would be 0.65*5716 = 3715.40. It was actually 298.50 less than that. Each bleacher ticket sold drops the revenue by .25, so there were 298.50/.25 = 1194 bleacher tickets sold.

3 0

2 years ago

Find the logarithmic function y = logbx that passes through the points

katovenus [111]

$b\in(0,\ 1)\ \cup\ (1,\ \infty)\\x > 0\\y\in\mathbb{R}\\--------------------------\\\\y=\log_bx\\\\For\ (1,\ 0)\to x=1,\ y=0.\ Substitute:\\\\\log_b1=0\to b^0=1\to b\in(0,\ 1)\ \cup\ (1,\ \infty)\\\\For\ (116,\ 2)\to x=116,\ y=2.\ Substitute:\\\\\log_b116=2\to b^2=116\to b=\sqrt{116}\\\to b=\sqrt{4\cdot29}\to b=\sqrt4\cdot\sqrt{29}\to b=2\sqrt{29}\\\\For\ (4,\ -1)\to x=4,\ y=-1.\ Substitute:\\\\\log_b4=-1\to b^{-1}=4\to b=\dfrac{1}{4}$

Different values of b.

<h3>Answer: There is no logarithmic function whose graph goes through given points.</h3><h3 />

Maybe the second point is $\left(\dfrac{1}{16},\ 2\right)$

Substitute:

$\log_b\dfrac{1}{16}=2\to b^2=\dfrac{1}{16}\to b=\sqrt{\dfrac{1}{16}}\to b=\dfrac{1}{4}$

<h3>Then we have the answer:</h3>

$\boxed{y=\log_{\frac{1}{4}}x}$

6 0

3 years ago