9 = 2(6) - b
9 = 12 - b
-3 = b
Total number of marbles in the bag =20
Number of blue marbles =4
Now we just want two blue marbles out of four.
Probability of taking out first marble which is blue =4/20
Now after we took out one blue marble , number of blue marbles left are 3.
Probability of taking out second marble which is blue =3/20
Total probability = 4/20 *3/20 = 12/400
So probability of taking out two blue marbles is 0.03 or 12/400.
1) add 7 to both sides and get -5....so -5 >x
2) add 7 to both sides.....so get b<-5
3) add 17 to both side...so get z>1
Answer:
N/A.
Step-by-step explanation:
I will not answer your question and I will be flagging it due to you adding a test/exam question.
Answer:
a(4) = 15/4
Step-by-step explanation:
Here we're told that the first term is a(1) = 30 and that the common factor r = 1/2.
Thus, the geometric sequence formula specific to this case is
a(n) = 30(1/:2)^(n-1).
What is the fourth term? Let n = 4,
a(4) = 30(1/2)^(4-1), or a(4) = 30(1/2)^(3), or a(4) = 30(1/8) = 30/8, or, in reduced form,
a(4) = 15/4.
