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2 years ago

Does cracking knuckles make your fingers fat

1 answer:

5 0

Yes . Cracking knuckles can even de-shape your fingers . In an older age , your joints could become weaker as compared to a normal person who practices less cracking of knuckles . It damages the hand's ligament .

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Why would we choose an embryonic mass of cells for procedure 14.3 in which to study for stages of mitosis?

Sati [7]

Embryonic mass cells are in constant division, making it much easier to find good examples of each phase of mitosis. The root and the stem are the best place to look because they contain meristematic tissue that retains the ability to divide throughout the life of the plant.

5 0

2 years ago

The chromosomal mutation in the zygote can be traced back to which of the following? (4.3, 4.4)Immersive Reader

lawyer [7]

The chromosomal mutation in the zygote can be traced back to "Chromosome 6 in the egg cell".

<u>Option: B</u>

<u>Explanation:</u>

In germ cells i.e. egg or sperm cells, the mutations in chromosome often happen during the meiosis phase. The number of chromosomes in egg cells or sperm cells must be haploid, so that diploid chromosomes form zygote on fertilization. Chromosome mutation in meiosis leads in an additional set of chromosomes or structural defects in the chromosome.

Chromosomal mutations are often caused by chemical agents or by mutagens. The homologous chromosomes are segregated from sister chromatids throughout cell division, any abnormality at this point allows the chromosomes to be unequally divided or not disjuncted, same is observed in the situation seen in egg cell chromosome 6.

3 0

2 years ago

I need help with the last two questions pleaseit’s due today.

Ivan

D) yes because in order to inherent a recessive trait you would have to have two recessive genes. In this case it’s (gg)
E)Yes because the parents have the genes (Hh) and (hh). (I’m assuming based off the first question) Therefore, if an offspring has hanging earlobes there’s a 50% chance they’d have the genes (Hh)

8 0

2 years ago

You are given two true-breeding groups of gerbils. The gerbils in the first group have black fur and curly tails; the gerbils in

Alexxx [7]

Answer:

3 black gebrils have straight tails

Explanation:

Given -

First group of true breeding gebrils have black fur and curly tails

Second group of true breeding gebrils have yellow fur and straight tails

After the F1 generation, all the offspring would have black fur and curly tail

This means black fur is dominant over yellow fur and curly tail is dominant over straight tails

Let "Black fur" be represented by "B" and "yellow fur" be represented by "b"

Let curly tail be represented by "C" and straight tail be represented by "c"

Then parents genotype for F1 generation would be "BBCC" and "bbcc"

and genotype of first generation offspring would be "BbCc"

BbCc

BC Bc bC bc

BC BBCC BBCc BbCC BbCc

Bc BBCc BBcc BbCc Bbcc

bC BbCC BbCc bbCC bbCc

bc BbCc Bbcc bbCc bbcc

Black Curly – BBCC, BBCc, BbCC, BbCc, BBCc, BbCc, BbCC, BbCc, Bbcc,

Yellow curly- bbCC, bbCc, bbCc

Black straight – BBcc, Bbcc, Bbcc

Yellow straight- bbcc

3 black gebrils have straight tails

6 0

2 years ago

Elements can combine to form molecules, like O2 or CO2. Elements combine to form molecules and these elements are joined togethe

Bad White [126]

D) attractive forces

7 0

3 years ago

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