Answer:
6.11km/hr
Step-by-step explanation:
Let the speed that Kelli swims be represented by Y
Speed of the river = 5km/hr
Distance = Speed × Time
Kelli swam upstream for some distance in one hour
Swimming upstream takes a negative sign, hence:
1 hour ×( Y - 5) = Distance
Distance = Y - 5
She then swam downstream the same river for the same distance in only 6 minutes
Downstream takes a positive sign
Converting 6 minutes to hour =
60 minutes = 1 hour
6 minutes =
Cross Multiply
6/60 = 1/10 hour
Hence, Distance =
1/10 × (Y + 5)
= Y/10 + 1/2
Equating both equations we have:
Y - 5 = Y/10 + 1/2
Collect like terms
Y - Y/10 = 5 + 1/2
9Y/10 = 5 1/2
9Y/ 10 = 11/2
Cross Multiply
9Y × 2 = 10 × 11
18Y = 110
Y = 110/18
Y = 6.1111111111 km/hr
Therefore, Kelli's can swim as fast as 6.11km/hr still in the water.
Answer:
<u>9π m²</u>
Step-by-step explanation:
We will need calculate the area of the top, the base and sides.
Area of the top=πr²
Area of the base=πr²
Area of the side: 2πrh
Surface area of a cylinder: area of the top + area of the base +area of the side
Surface area of a cylinder=πr²+πr²+2πrh=2πr²+2πrh=2πr(r+h)
Data:
r=1.5 m
h=1.5 m
Surface area of this cylinder=2π(1.5m)(1.5 m+1.5 m)=3π m*(3 m)=9π m².
The distance between two points knowing theirs coordinates:
AB =√[(x₂-x₁)² +(y₂-y₁)²]; ===>A(-2,4) & B(0,-6) Given
A(x₁,y₁) & B(y₂,y₁)
AB =√[(0-(-2))²+(-6-4)²] =√(104) = 10.198 ≈ 10.2
Answer:
30.8936
Step-by-step explanation:
Pressure guage reading is 8% lower than tbe actual pressure.
Therefore, for a tyre with guage pressure, 33.58 ;
The actual pressure of tyre would be :
Guage pressure - 8% of guage pressure
33.58 - (0.08 * 33.58)
33.58 - 2.6864
= 30.8936
Actual pressure = 30.8936