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frosja888 [35]
3 years ago
14

Use the Central Limit Theorem to find the mean and standard error of the mean of the indicated sampling distribution. The monthl

y rents for studio apartments in a certain city have a mean of $ 1 comma 060 and a standard deviation of $ 190. Random samples of size 30 are drawn from the population and the mean of each sample is determined. Round the answers to the nearest hundredth.
Mathematics
1 answer:
malfutka [58]3 years ago
4 0

Answer:

Mean $1060

Standard error $34.69

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation, which is also called standard error, s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Population:

Mean $1,060 and standard deviation $190.

Sampling distriution of samples of size 30:

Mean $1060

Standard deviation s = \frac{190}{\sqrt{30}} = 34.69

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