Answer:
ABCDEFGHIJKLMNOPQRSTUFWTYZ
Step-by-step explanation:
Answer:
The probability P of a day with no perceptible earthquakes is 0.0821.
Step-by-step explanation:
We will consider that earthquakes occurring in a day is a <u>Poisson process</u>. The following Poisson probability distribution formula will be used in this question.
<u>p(x,λ) = [e^-λ (λ)ˣ]/x!</u>
where x = number of outcomes occurring
λ = mean number of occurrences
(a) So, in this question we have λ = 2.5 and we need to find the probability that x=0 (no perceptible earthquakes in a day). So,
P(X=0) = p(0,2.5) = [(e^-2.5)(2.5)⁰]/0!
= ((0.0821)*1)/1
P(X=0) = 0.0821
The probability P of a day with no perceptible earthquakes is 0.0821.
Answer:
-3'1
-6'1
Step-by-step explanation:
the bottom left and top right are always going to be negative. The right top and bottom are positive numbers. so the answer is -3'1 for the first top one then the second bottom dot is -6'1
Answer: 18.75
Step-by-step explanation:There are 24 hours in a day. 4 hours 30 minutes is 4.50 hours. Which is equal to 18.75%.
So you have to solve for "donation" - so let's call that X. And the things we know are what the grandfather donated, as a function - meaning based upon - Theo's donation. We'll call that Y.
So Y is equal to 1/2 of $4 plus Theo's donation...... 0.5*(x+4).
So... 4.25 = 0.5(X+4), solving for X
4.25=0.5x + 2
-2 -2
2.25=0.5x - divide each side by 0.5 to get x alone.
x = 4.50
Plugging back in:
(4.50 + 4.00)*0.5 = 4.25!
